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White raven [17]
3 years ago
5

You want to lift a heavy box with a mass L = 56.0 kg using the two-ideal pulley system as shown. With what minimum force do you

have to pull down on the rope in order to lift the box at a constant velocity? One pulley is attached to the ceiling and one to the box.
Physics
1 answer:
Olin [163]3 years ago
3 0

The minimum force required to lift the box at constant velocity is determined as 274.4 N.

<h3>Minimum force required</h3>

The minimum force required to lift the box at constant velocity is the tension in one of the pulleys, and the magnitude is calculated as follows;

2T = mg

where;

  • m is mass of the box
  • T is the minimum force required

2T = mg

T = mg/2

T = (56 x 9.8)/2

T = 274.4 N

Learn more about minimum force here: https://brainly.in/question/47873510

#SPJ1

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The gas- powered mower is

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6 0
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An observer notices that 12 waves pass by in 4 seconds. What is the frequency of these waves? 0.33 Hz 16 Hz 48 Hz 3 Hz
Dennis_Churaev [7]

Answer:

Frequency = 3 Hz

Explanation:

Frequency is a measure of Hertz. Recall that Hertz is the unit expressing cycles/second, where one second is the denominator of the fraction for simplicity. If there are 12 waves every four seconds, and one wave represents one cycle, dividing 12 waves by 4 seconds will give the answer of 3 waves (or cycles) per one second.

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What is the cause of atmospheric pressure.​
marusya05 [52]

Explanation:

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6 0
3 years ago
On a straight road (taken to be in the +x direction) you drive for an hour at 50 km per hour, then quickly speed up to 90 km per
dalvyx [7]

Answer:

a) 230 Km b) 76.7 km/h c) Please see below

Explanation:

a) If we can neglect the time while the driver accelerated, the movement can be divided in two parts, each of them at a constant speed:

x = x1 + x2  \\\\x1 = 50 km/h* 1hr = 50 km, \\x2 = 90 Km/h*2hr = 180 km\\

⇒ x = 50 km + 180 km = 230 km

b) The average x component of velocity, can be calculated applying the definition of average velocity, as follows:

vavg,x = \frac{xf-xo}{t-to}

If we choose t₀ = 0 and x₀ = 0, replacing xf and t by the values we have already found, we can find vavg,x as follows:

vavg,x =\frac{230 km}{3 hr} =76.7 km/h

c) The found value of  avg,x is not the same as the arithmetic average of the initial and final values of vx (70 Km/h) due to the time traveled at both velocities was not the same.

If the driver had droven half of the time (1.5 h) at 50 km/h and the other half at 90 km/h, total displacement would have been as follows:

x = 50 km/h*1.5 h + 90 km/h*1.5 hr = 210 km

Applying the definition of average velocity once more:

vavg,x =\frac{210 km}{3 hr} =70 km/h

which is the same as the arithmetic average of the initial and final values of vₓ.

7 0
3 years ago
Suppose a family replaces ten 60-watt incandescent bulbs with ten 30-watt
mixer [17]

Initially there were 10 bulbs of 60 Watt power

So total power of all bulbs = 60 * 10 = 600 W

now each bulb used for 4 hours daily

so total energy consumed daily

E = p*t

E = 600*4 = 2400Wh

E = 2.4kWH

now we have total power consumed in 1 year

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cost of electricity = 10 cents/ kWh

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Now if all 60 Watt bulbs are replaced by 30 Watt bulbs

So total power of all bulbs = 30 * 10 = 300 W

now each bulb used for 4 hours daily

so total energy consumed daily

(The next steps are in the pic.)

5 0
3 years ago
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