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grandymaker [24]
3 years ago
14

What does it mean to say that a hypothesis is falsifiable

Chemistry
2 answers:
erastovalidia [21]3 years ago
8 0

Answer:

is means it can be proven false

Lelu [443]3 years ago
7 0

Answer: This means that the answer can be proven wrong.

Explanation:

Hope this helps!!

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The plunger on a bicycle pump with a 400 mL volume cylinder is
Kobotan [32]

Answer:

The answer to your question is V2 = 66.7 ml

Explanation:

Data

Volume 1 = V1 = 400 ml

Pressure 1 = P1 = 1 atm

Volume 2 = V2 = ?

Pressure 2 = P2 = 6 atm

Process

1.- To solve this problem use Boyle's law

                     P1V1 = P2V2

-solve for V2

                     V2 = P1V1 / P2

-Substitution

                      V2 = (1)(400) / 6

-Simplification

                      V2 = 400 / 6

-Result

                      V2 = 66.7 ml

4 0
3 years ago
What is the name of the functional group in this compound?
NISA [10]
The characteristic of the compound you are referring is essential to where on the functional groups it belong. Furthermore, the basic functional groups among the hydrocarbons are: alkane, alkene, alkyne, benzene, and others that basically has a hydrogen atom and a carbon atom.
8 0
3 years ago
Read 2 more answers
water (H2O) and carbon dioxide (CO2) are similar because they both contain at least one oxygen A.) atom. B.) mixture C.) molecul
vova2212 [387]

Answer:

a

Explanation:

it is A because h20 and c02 are molecules while what make them up are atoms

5 0
3 years ago
Read 2 more answers
A motor “runs” when what is produced by a spinning magnet ?
alex41 [277]

Answer:

electrical energy

Explanation:

its just right

7 0
3 years ago
A 25.0 g piece of aluminum (which has a molar heat capacity of 24.03 J/mol°C) is heated to 86.4°C and dropped into a calorimeter
Ira Lisetskai [31]

Answer:

m H2O = 56 g

Explanation:

  • Q = mCΔT

∴ The heat ceded (-) by the Aluminum part is equal to the heat received (+) by the water:

⇒ - (mCΔT)Al = (mCΔT)H2O

∴ m Al = 25.0 g

∴ Mw Al = 26.981 g/mol

⇒ n Al = (25.0g)×(mol/26.981gAl) = 0.927 mol Al

⇒ Q Al = - (0.927 mol)(24.03 J/mol°C)(26.8 - 86.4)°C

⇒ Q Al = 1327.64 J

∴ mH2O = Q Al / ( C×ΔT) = 1327.64 J / (4.18 J/g.°C)(26.8 - 21.1)°C

⇒ mH2O = 55.722 g ≅ 56 g

5 0
3 years ago
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