Answer:
C) 1.3 mol
Explanation:
Using gas law we can find the initial moles of the sample of the mixture, as follows:
PV = nRT
PV / RT = n
<em>Where P is pressure: 4.0atm</em>
<em>V is volume: 9.6L</em>
<em>R is gas constant: 0.082atmL/molK</em>
<em>T is absolute temperature: 300K</em>
<em>And n are moles of the gas</em>
<em />
PV / RT = n
4.0atm*9.6L / 0.082atmL/molK300K = n
n = 1.56moles of the mixture of the gas are present into the 9.6L container
Now, 14% of this gas is hydrogen that was removed of the system, that is:
1.56mol*14% = 0.22 moles of hydrogen are removed.
Thus, moles of gas that remains in the container are:
1.56mol - 0.22mol = 1.34mol.
Right answer is:
<h3>C) 1.3 mol</h3>
Answer:
Kc = 1.54e - 31 / 2.61e - 24
Explanation:
1 ) 
; Kc = 1.54e - 31
2) 
; Kc = 2.16e - 24
upon reversing ( 2 ) equation
Kc = 1/2.16e - 24
now adding 1 and reversed equation (2)
we get ,
Kc = 1.54e-31 × 1/2.61e - 24
equilibrium constant of equation (3) is -
Kc = 1.54e - 31 / 2.61e - 24
Mass of KNO₃ : = 40.643 g
<h3>Further explanation</h3>
Given
28.5 g of K₃PO₄
Required
Mass of KNO₃
Solution
Reaction(Balanced equation) :
2K₃PO₄ + 3 Ca(NO₃)₂ = Ca₃(PO₄)₂ + 6 KNO₃
mol K₃PO₄(MW=212,27 g/mol) :
= mass : MW
= 28.5 : 212,27 g/mol
= 0.134
Mol ratio of K₃PO₄ : KNO₃ = 2 : 6, so mol KNO₃ :
= 6/2 x mol K₃PO₄
= 6/2 x 0.134
= 0.402
Mass of KNO₃ :
= mol x MW KNO₃
= 0.402 x 101,1032 g/mol
= 40.643 g
Its atomic symbol is H and its atomic number is one. Hydrogen; Hydrogen, H, is a chemical element with atomic number 1. At standard temperature and pressure, hydrogen is a colorless, odorless, nonmetallic, tasteless, highly flammable diatomic gas with the molecular formula H2.
Hydrogen is easily the most abundant element in the universe. It is found in the sun and most of the stars, and the planet Jupiter is composed mostly of hydrogen. On Earth, hydrogen is found in the greatest quantities as water.
D would be your best bet because evaporation occurs when water is heated, it then vibrates and then magic!
