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Marta_Voda [28]
3 years ago
6

Jess shares £60 in the ratio 3:4

Mathematics
1 answer:
Nataliya [291]3 years ago
7 0

Answer:

Amount of money share by Jess = £25.70

Another Amount of money share by Jess = £34.3

Step-by-step explanation:

Given:

Amount of money Jess have = £60

Sharing ratio = 3 : 4

Find:

Amount of money share by Jess

Computation:

Sharing amount = Shared ratio / Sum of ratio

Amount of money share by Jess = 60[3/(3+4)]

Amount of money share by Jess = 60[3/(7)]

Amount of money share by Jess = 180 / 7

Amount of money share by Jess = £25.70

Another Amount of money share by Jess = £60 - £25.70

Another Amount of money share by Jess = £34.3

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I need help with this ASAP!!!
hjlf

Answer:

sqrt d = 10

d = (10)^2

d = 100

Part b

x^2 = 144

x = 12 or -12

Step-by-step explanation:

4 0
3 years ago
I need help with my IXL long terms. Can someone help/tell me how to do them????
ivanzaharov [21]
The answer to this is y=x+5
8 0
3 years ago
CAN SOMEONE PLEASE HELP WILL GIVE BRAINLIEST
spin [16.1K]

Answer:

c = 7

d = 5

Step-by-step explanation:

Notice that in the first expression, x^c is inside a square root, and only perfect squares can be extracted from it. On the simplified form shown on the right hand side, we have x^3 outside the root and a single "x" left inside. In order for such to happen (x^3 get outside the root) there must have been an x^6 inside the square root. This together with the sole "x" that was left in the root, totals seven factors of x that should have been originally inside the square root:

x^6 * x = x^7  therefore c was a "7"

In the second expression we have a CUBIC root, so only perfect cubes can get extracted from it. Since there is one factor "x" shown in the simplified form (right hand side of the equal sign), that means that it must have been an x^3 (perfect cube) apart from the x^2 that was left inside the root. This makes the original power of x to be a 3 + 2 = 5.

Therefore d = 5

4 0
3 years ago
What is not a composite number out of 2 4 6 8
sattari [20]

Answer:

2

Step-by-step explanation:

2 has the factors 2 and 1 while the others have:

4- 4, 2,1

6- 6, 3, 2, 1

8- 8, 4, 2, 1

3 0
3 years ago
A bag contains 3 red balls and 1 blue ball. A second bag contains 1 red ball and 1 blue ball. A ball is randomly picked from eac
Firlakuza [10]

Answer:

"2.82" seems to be the correct solution.

Step-by-step explanation:

As we know,

A bag (Bag A) contains,

Red balls = 3

Blue ball = 1

A second bag (Bag B) contains,

Red balls = 1

Blue ball = 1

Now,

⇒ P(Bag A, red ball) = P(A)\times P(r)\times P(r)

On substituting the values, we get

⇒                                = \frac{1}{2}\times \frac{3}{4}\times \frac{2}{3}

⇒                                = \frac{1}{4}

Similarly,

Probability of second bag will be:

⇒  P(Bag B) = \frac{1}{2}

hence,

In the first bag (Bag A), the expected number of red balls will be:

⇒  E(n)=\Sigma P(n)\times n

On substituting the values, we get

⇒           =3 (\frac{1}{4})+2(\frac{1}{8} )+4(\frac{1}{24} )+3(\frac{1}{12} )+3(\frac{4}{20} )+4(\frac{1}{20} )+2(\frac{3}{20} )+\frac{2}{20}

⇒           = \frac{169}{60}

⇒           =2.82

7 0
3 years ago
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