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blagie [28]
3 years ago
13

A transformer is a device used to increase or decrease the voltage through induction. Which fundamental force is responsible for

this induction?ElectromagneticWeak NuclearStrong NuclearGravitational
Physics
1 answer:
dlinn [17]3 years ago
5 0

The two nuclear forces are not responsible for this property.

Gravitational is far too weak to make a transformer work.

The answer is electromagnetic.

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A race car exerts 18,344 N while the car travels at an acceleration of 92.54 m/s2. What is the mass of the car? (Use the formula
Maru [420]

Answer:

<h3>The answer is 198.23 kg</h3>

Explanation:

To find the mass of an object given it's mass and acceleration we use the formula

m =  \frac{f}{a}  \\

where

m is the mass

F is the force

a is the acceleration

From the question

a = 92.54 m/s²

F = 18,344 N

We have

m =  \frac{18344}{92.54}  \\  = 198.2277933...

We have the final answer as

<h3>198.23 kg</h3>

Hope this helps you

4 0
4 years ago
Read 2 more answers
What is the mass of modelling clay?​
Maurinko [17]

the mass of modelling clay is 500g

6 0
3 years ago
Read 2 more answers
An astrophysicist mounts two thin lenses along a single optical axis (the lenses are at right angles to the line connecting them
Alexandra [31]

Answer:

1 / i + 1 / o = 1 / f     thin lens equations

i = o f / (o - f)   rearranging

Lens 1:   object = 30 cm    f = 15.2 cm

i1 = 30 * 15.2 / (30 - 15.2) = 30.8 cm

o2 = 40.2 - 30/8 = 9.4 cm    distance of image 1 from lens 2

i2 = 9.4 * 15.2 / (9.4 - 15.2) = - 24.6 cm

The final image is 24.6 cm to the left of lens 2

The first image is inverted

The second image is erect (as seen from the first image)

So the final image is inverted

M = m1 * m2 = (-30.8 / 30) * (24.6 / 9.4) = -2.69

7 0
3 years ago
The combination of all forces that act on an object are (2 points)
qaws [65]

Answer:

A) The net force

Explanation:

If two forces of equal strength act on an object in opposite directions, the forces will cancel, resulting in a net force of zero and no movement.

5 0
4 years ago
(a) Suppose that your measured weight at the equator is one-half your measured weight at the pole on a planet whose mass and dia
stealth61 [152]

Answer:

7160.2812 s or 1.988 hours

Explanation:

m = Mass of person

R = Radius of Earth = 6.37\times 10^{6}\ m

g = Acceleration due to gravity = 9.81 m/s²

\omega = Angular speed

Force at equator would be

F_e=m(g-\omega^2R)

Force at pole

F_p=mg

From the question

F_e=\dfrac{1}{2}F_p\\\Rightarrow m(g-\omega^2R)=\dfrac{1}{2}F_p\\\Rightarrow \omega=\sqrt{\dfrac{g}{2R}}

Time period is given by

T=\dfrac{2\pi}{\omega}\\\Rightarrow T=2\pi\sqrt{\dfrac{2R}{g}}\\\Rightarrow T=2\pi\sqrt{\dfrac{2\times 6.37\times 10^6}{9.81}}\\\Rightarrow T=7160.2812\ s=1.988\ hours

The rotational period of the planet is 7160.2812 s or 1.988 hours

5 0
3 years ago
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