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Phantasy [73]
3 years ago
9

Olivia noticed that it took 2s for a wave to pass by where she was swimming. What property of a wave did she measure?

Physics
1 answer:
Bumek [7]3 years ago
6 0

The only thing about a wave that has units of time is the wave's <em>PERIOD</em>.

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A stationary, 1000 kg car starts at the top of a 10 meter hill. What is the total energy of the car
Umnica [9.8K]

Answer: 98,000 J

Explanation: The total energy or mechanical energy is expressed in the following equation:

ME= PE + KE

PE = mgh

= 1000 kg x 9.8 m/s² x 10m

= 98000 J

ME = PE - KE

= 98000 J - 0 J

= 98000 J

7 0
4 years ago
Read 2 more answers
How can all matter on Earth be classified?
Dvinal [7]

Answer:

by helping

Explanation:

u see the answer is by helping cause cleaning the earth help and helpingb animals so it would be helping

3 0
3 years ago
Read 2 more answers
A que profundidad esta nadando una persona dentro de una alberca si la presión absoluta sobre ésta es de 156kPa?
lara31 [8.8K]

Answer:

La persona está nadando en la alberca a una profundida de 5.575 metros.

Explanation:

La presión absoluta (P_{tot}) experimentada por la persona es la suma de la presión atmosférica (P_{atm}) y la presión hidrostática de la columna de agua de la alberca (P_{h}), medidas en kilopascales. Es decir,

P_{tot} = P_{atm}+P_{h} (1)

P_{tot} = P_{atm} + \frac{\rho\cdot g \cdot z}{1000} (2)

Donde:

\rho - Densidad del fluido de la alberca, medida en kilogramos por metro cúbico.

g - Aceleración gravitacional, medida en metros por segundo al cuadrado.

z - Profundidad de la persona en la alberca, medida en metros.

Si sabemos que P_{atm} = 101.325\,kPa, \rho = 1000\,\frac{kg}{m^{3}}, g = 9.807\,\frac{m}{s^{2}} y P_{tot} = 156\,kPa, entonces la profundidad de la persona en la alberca es:

156 = 101.325 +\frac{(1000)\cdot (9.807)\cdot z}{1000}

54.675 = 9.807\cdot z

z = 5.575\,m

La persona está nadando en la alberca a una profundida de 5.575 metros.

5 0
3 years ago
A rocket is fired vertically upwards with initial velocity 92 m/s at the ground level. Its engines then fire and it is accelerat
Readme [11.4K]

Answer:

The rocket above the ground is in 44 sec.

Explanation:

Given that,

Initial velocity = 92 m/s

Acceleration = 4 m/s²

Altitude = 1200 m

Suppose, How long was the rocket above the ground?

We need to calculate the time

Using equation of motion

s=ut-\dfrac{1}{2}at^2

Put the value into the formula

1200=92t+\dfrac{1}{2}\times4t^2

2t^2+92-1200=0

t=10\ sec

We need to calculate the velocity

Using equation of motion

v=u+at

Put the value into the formula

v=92+4\times10

v=132\ m/s

When the rocket hits the ground,

Then, h'=0

We need to calculate the time

Using equation of motion

h'=h+ut-\dfrac{1}{2}at^2

Put the value into the formula

0=1200+132t-\dfrac{1}{2}\times9.8t^2

4.9t^2-132t-1200=0

t=34\ sec

When the rocket is in the air it is the sum of the time when it reaches 1000 m and the time when it hits the ground

So, the total time will be

t'=34+10

t'=44\ sec

Hence, The rocket above the ground is in 44 sec.

7 0
4 years ago
Need help with this science!!
noname [10]
Lol, I remember I helped my sister with this question but anyways, the card flew because of inertia and the quarter fell in the glass because of gravity :).
3 0
3 years ago
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