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2 years ago

How do I solve this algebra problem: 2(4a-12)+3a=6a+1

Mathematics

2 answers:

umka21 [38]2 years ago

6 0

$2(4a-12)+3a=6a+1 \\\\ 8a-24+3a=6a+1 \\\\ 11a-24=6a+1 \\\\ 11a-6a=1+24 \\\\ 5a=25 \\\\ \boxed{a=\frac{25}{5}=5}$

Len [333]2 years ago

4 0

$2(4a-12)+3a=6a+1\\\\
8a-24+3a=6a+1\\\\
11a-24=6a+1\ \ \ |Subtract\ 6a\\\\
5a-24=1\ \ \ |Add\ 24\\\\
5a=25\ \ \ |Divide\ by\ 5\\\\
a=5\\\\Solution\ is\ a=5.$

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2 years ago

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pashok25 [27]

Answer:

$\large\boxed{V=\dfrac{1,421\pi}{3}\ cm^3}$

Step-by-step explanation:

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R - radius

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$V_{hs}=\dfrac{1}{2}\cdot\dfrac{4}{3}\pi R^3=\dfrac{2}{3}\pi R^3$

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