Question

How do I solve this algebra problem: 2(4a-12)+3a=6a+1

Answer 1

$2(4a-12)+3a=6a+1 \\\\ 8a-24+3a=6a+1 \\\\ 11a-24=6a+1 \\\\ 11a-6a=1+24 \\\\ 5a=25 \\\\ \boxed{a=\frac{25}{5}=5}$

Answer 2

$2(4a-12)+3a=6a+1\\\\ 8a-24+3a=6a+1\\\\ 11a-24=6a+1\ \ \ |Subtract\ 6a\\\\ 5a-24=1\ \ \ |Add\ 24\\\\ 5a=25\ \ \ |Divide\ by\ 5\\\\ a=5\\\\Solution\ is\ a=5.$