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3 years ago

Plz help me with this

Mathematics

2 answers:

Mrac [35]3 years ago

6 0

4/5*3/7=a
a=12/35
12/35 square units

marysya [2.9K]3 years ago

5 0

7/12=a square units or 12/35=a

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The mean score of 8 players is 14.5. If the highest individual score is removed the mean of the score of the remaining 7 players

AfilCa [17]

Answer:

The highest score is 32.

Step-by-step explanation:

We are given the following in the question:

The mean score of 8 players is 14.5.

Let x denote the highest score.

If x is removed, the mean of the score of the remaining 7 players is 12.

Formula for mean:

$\bar{x} = \dfrac{\displaystyle\sum x_i}{n}$

Putting values, we get:

$14.5 = \dfrac{\displaystyle\sum x_i}{8}\\\\\Rightarrow \displaystyle\sum x_i = 116\\\\12 = \dfrac{\displaystyle\sum y_i}{7}\\\\\Rightarrow \displaystyle\sum y_i = 84\\\\\displaystyle\sum y_i = \displaystyle\sum x_i -x \\\\84 = 116 - x\\\Rightarrow x = 32$

Thus, the highest score is 32.

4 0

4 years ago

Whoever answers this will get 99 points

GrogVix [38]

To find the sum of circumference, the equation is
C = 2πr

C = 2πr is your answer

hope this helps

7 0

4 years ago

Read 2 more answers

!!!!PLEASE HELP!!!!!2 QUESTION

anygoal [31]

So according to the picture you sent the first part is 2(x-8) (x+6)=0 so it’s the first answer. The second part the answer is (8;0) and (-6;0) the last answer in the second frame.
The reason the answer is those is because it’s using coordinates (x;y) and since we were solving for x we got the x coordinates. But since we got the x coordinates our y coordinates will be 0. If the answer was y=8 than out coordinates would be (0;8). Hope this makes sense

Please mark as brainliest

7 0

3 years ago

Use the unit circle to evaluate these expressions:

sergeinik [125]

Answer:

a) We can remove the complete rotations around the unitary circle like this, because we know that one complete revolution is equivalent to $2\pi$ :

$17 \pi/4 - 2\pi = \frac{9\pi}{4} -2\pi = \pi/4$

For this case we know that $sin (\pi/4) = \frac{\sqrt{2}}{2}$

So then $sin(\frac{17 \pi}{4}) = \frac{\sqrt{2}}{2}$

b) We can remove the complete rotations around the unitary circle like this, because we know that one complete revolution is equivalent to $2\pi$ :

$19 \pi/6 - 2\pi = \frac{7\pi}{6}$

For this case we know that $cos (\pi/6) = \frac{\sqrt{3}}{2}$

And we know that $\frac{7\pi}{6}$ is on the III quadrant since is equivalent to 210 degrees. And on the III quadrant the cosine is negative. So then $cos(\frac{19 \pi}{6}) = -\frac{\sqrt{3}}{2}$

c) For this case that any factor of $\pi$ the sin function is equal to 0.

So from definition of tan we have this:

$tan (450\pi) = \frac{sin(450 \pi)}{cos(450 \pi)}= \frac{0}{cos(450\pi)}= 0$

Step-by-step explanation:

a. sin (17pi / 4 )

We can remove the complete rotations around the unitary circle like this, because we know that one complete revolution is equivalent to $2\pi$ :

$17 \pi/4 - 2\pi = \frac{9\pi}{4} -2\pi = \pi/4$

For this case we know that $sin (\pi/4) = \frac{\sqrt{2}}{2}$

So then $sin(\frac{17 \pi}{4}) = \frac{\sqrt{2}}{2}$

b. cos (19pi / 6 )

We can remove the complete rotations around the unitary circle like this, because we know that one complete revolution is equivalent to $2\pi$ :

$19 \pi/6 - 2\pi = \frac{7\pi}{6}$

For this case we know that $cos (\pi/6) = \frac{\sqrt{3}}{2}$

And we know that $\frac{7\pi}{6}$ is on the III quadrant since is equivalent to 210 degrees. And on the III quadrant the cosine is negative. So then $cos(\frac{19 \pi}{6}) = -\frac{\sqrt{3}}{2}$

c. tan(450pi)

For this case that any factor of $\pi$ the sin function is equal to 0.

So from definition of tan we have this:

$tan (450\pi) = \frac{sin(450 \pi)}{cos(450 \pi)}= \frac{0}{cos(450\pi)}= 0$

4 0

3 years ago

Can sumone help Mii wit thiss??

SpyIntel [72]

Equal them to each other

7 0

3 years ago