Answer:
Step-by-step explanation:
1) Vertex form of a quadratic equation is y=a(x-h)2+k, where (h,k) is the vertex of the parabola.
2) The vertex of a parabola is the point at the top or bottom of the parabola.
3) 'h' is -6, the first coordinate in the vertex.
4) 'k' is -4, the second coordinate in the vertex.
5) 'x' is -2, the first coordinate in the other point.
ANSWER:
84; Consecutive Interior Angles Theorem
Answer: The required ratio will be

Step-by-step explanation:
Since we have given that
Ratio of AD to AB is 3:2
Length of AB = 30 inches
So, it becomes

So, Length of AD becomes

Now, at either end , there is a semicircle.
Radius of semicircle along AB is given by

So, Area of semicircle along AB and CD is given by

Radius of semicircle along AD is given by

Area of semicircle along AD and BC is given by

And the combined area of the semicircles is given by

Area of rectangle is given by

Hence, Ratio of the area of the rectangle to the combined area of the semicircles is given by

Hence, the required ratio will be

Answer:
Step-by-step explanation:
a) Yes.

b) Yes

c) Yes

d) No

If 4·10= 40 then 4·-10 would equal -40 bc a positive times a negative equals a negative.
Hope this helped!!