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djyliett [7]
3 years ago
8

Please answer this question

Mathematics
1 answer:
polet [3.4K]3 years ago
3 0
The domain of the graph is less than or equal to 0.
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What are the domain and range of f(x) = |x + 6|?
san4es73 [151]

9514 1404 393

Answer:

  • domain: all real numbers
  • range: y ≥ 0

Step-by-step explanation:

The function is defined for all values of x, so its domain is all real numbers.

The function can produce values of f(x) that are 0 or greater, so its range is ...

  y ≥ 0

4 0
2 years ago
2. Multiple Choice. Gary says, “I chose a number. I multiplied it by 5 and then
kkurt [141]

Answer:

The answer would be B

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3 years ago
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In the situation, simple interest is calculated yearly. How much interest was earned? (Answers above)
Ket [755]
The simple interest formula<span> allows us to calculate I, which is the </span>interest<span> earned or charged on a loan. According to this </span>formula<span>, the amount of </span>interest<span> is given by I = Prt, where P is the principal, r is the annual </span>interest<span> rate in decimal form, and t is the loan period expressed in years.

I = Prt
I = 5500 (8) (0.025) = 1100  <----second option</span>
3 0
3 years ago
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Is the quotient of 9 rational
Musya8 [376]
Yes the quotient of 9 is rational
4 0
3 years ago
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The figure shows △ABC . BD is the angle bisector of ∠ABC .
Misha Larkins [42]
From angle bisector theorem, we know that:

\dfrac{|AD|}{|DC|}=\dfrac{|BA|}{|BC|}\\\\\\\dfrac{|AD|}{|DC|}=\dfrac{8}{10}=\dfrac{4}{5}

Moreover:

|AD|+|DC|=6

so:

|DC|=6-|AD|

and

\dfrac{|AD|}{|DC|}=\dfrac{4}{5}\\\\\\\dfrac{|AD|}{6-|AD|}=\dfrac{4}{5}\qquad\qquad\text{cross multiplying}\\\\\\ 5\cdot|AD|=4\cdot\big(6-|AD|\big)\\\\5\cdot|AD|=24-4\cdot|AD|\\\\5\cdot|AD|+4\cdot|AD|=24\\\\9\cdot|AD|=24\qquad|:9\\\\\\|AD|=\dfrac{24}{9}=\boxed{\dfrac{8}{3}}

3 0
3 years ago
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