Answer:
put something to answer next time maybe.
Step-by-step explanation:
Put a picture in.
The answer is 256 ,
explanation- 6+2 is 8 and 36-4 is 32. 8 times 32= 256
Step-by-step explanation:
If half of the tuna sandwiches were on white bread then 21 of them would be white, meaning the other half would be on brown bread.
Then if 25% of ham sandwiches were on brown bread then 25% of 32 would be 8, so the final 75% would be on white bread, which would be 24.
Finally, with 20 more white bread sandwiches sold than brown bread it couldn’t be 80 and 20, it would be 40 brown bread in total and 60 white bread in total adding up to 100, as it says white sells 20 more than brown not only 20.
To finish this question you would add up the tuna and ham for white (21+24=45) then minus that from 60 (60-45=15) so there were 15 cheese sandwiches on white bread. And then for brown (21+8=29) then minus that from 40 (40-29=11) so therefore there are 11 cheese sandwiches on brown bread.
Answer:
Brown:
Tuna-21
Cheese-11
Ham-8
Total-40
White:
Tuna-21
Cheese-15
Ham-24
Total-60
Hope that helps!
Using Laplace transform we have:L(x')+7L(x) = 5L(cos(2t))sL(x)-x(0) + 7L(x) = 5s/(s^2+4)(s+7)L(x)- 4 = 5s/(s^2+4)(s+7)L(x) = (5s - 4s^2 -16)/(s^2+4)
=> L(x) = -(4s^2 - 5s +16)/(s^2+4)(s+7)
now the boring part, using partial fractions we separate 1/(s^2+4)(s+7) that is:(7-s)/[53(s^2+4)] + 1/53(s+7). So:
L(x)= (1/53)[(-28s^2+4s^3-4s^2+35s-5s^2+5s)/(s^2+4) + (-4s^2+5s-16)/(s+7)]L(x)= (1/53)[(4s^3 -37s^2 +40s)/(s^2+4) + (-4s^2+5s-16)/(s+7)]
denoting T:= L^(-1)and x= (4/53) T(s^3/(s^2+4)) - (37/53)T(s^2/(s^2+4)) +(40/53) T(s^2+4)-(4/53) T(s^2/s+7) +(5/53)T(s/s+7) - (16/53) T(1/s+7)
