Inv1 investment 1
inv2 investment 2
A) inv1 + inv2 = 33,000
B) .04 inv1 + .07 inv2 = 1,950
Multiplying A) by -.04
A) -.04 inv1 - .04 inv2 = -1,320
Then adding B)
B) .04 inv1 + .07 inv2 = 1,950
.03 inv2 = 630
inv2 = 630 / .03
inv2 = 21,000 invested at 7%
inv1 = 33,000 -21,000=
12,000 invested at 4%
Answer: Union of two sets.
Explanation: "An element is in the union of two sets if it is in the first set, the second set, or both. The symbol we use for the union is ∪ . The word that you will often see that indicates a union is "or".
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Answer:
<h2>
(e³ - 1)/3e²</h2>
Step-by-step explanation:
Given the function y = e^x between the interval x = -2 and x =1, the average rate of change for the function will be the slope of the function expressed as m = Δy/Δx where;
Δy = f(b)-f(a) and Δx = b-a
m = f(b)-f(a)/b-a where a and b is the interval [-2, 1]
m = f(1)-f(-2)/1-(-2)
m = f(1)-f(-2)/3
Given the function f(x) = e^x,
at the end point x = b, f(1) = e^1; f(1) = e
at the end point x = a, f(-2) = e^-2; f(-2) = 1/e²
m = (e - 1/e²)/3
m = [(e³ - 1)/e²]/3
m = (e³ - 1)/e² * 1/3
m = (e³ - 1)/3e²
Hence, the average rate of change for the function at the interval [-2, 1] is (e³ - 1)/3e²
The number 24,316 can't be rounded to the nearest tenth because it doesn't have any decimal numbers.
The answer is the first one because 7 times 1000 is 7000, 2 times 100 is 200, 9 times 1 is 9, 3 times 1/10 is 3/10 or 0.3, and 6 times 1/1000 is .006.
added together, the number is 7209.306