The work of a student to solve a set of equations is shown below: Equation 1: x + 2y = 10 Equation 2: 2x + 5y = 15 Step 1: −2(x
2 answers:
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Answer: 0.99822
Step-by-step explanation:
Our inter-arrival time follows Poisson distribution with parameter 14 which is in hour so first we have to calculate this in minutes as we have to calculate probability in minutes.
So converting 14 into minutes will give =0.233
Let X=inter-arrival time between two customers
and here = 0.233
Probability(X is less than or equal to 2 minutes) = P(X=0) + P(X=1) + P(X=2)
Now the Poisson distribution has PDF =
So P(X = 0) = = 0.79215
P(X= 1) = = 0.18457
P(X=2) = = 0.02150
Now adding all three probability gives = 0.79215 +0.18457 + 0.02150=0.99822
Answer:
The number of individuals included in the summary is 146.
Step-by-step explanation:
The frequency distribution table provided is as follows:
Class Intervals Frequency
100 - 199 24
200 - 299 90
300 - 399 27
400 - 499 1
500 - 599 4
The lower class limit it the smallest value of each class interval.
Lower class limit = {100, 200, 300, 400, 500}
The upper class limit it the highest value of each class interval.
Upper class limit = {199, 299, 399, 499, 599}
The lower class boundaries are the lower class limits decreased by 0.5 and the upper class boundaries are the upper class limits increased by 0.5.
Class boundaries:
99.5 - 199.5
199.5 - 299.5
299.5 - 399.5
399.5 - 499.5
499.5 - 599.5
The class width is the difference between the class boundaries of each class.
Class width = 199.5 - 99.5 = 100
So, the class width is 100.
The midpoints of a class is the average value of the boundaries of a class.
The number of individuals included in the summary is the sum of all frequencies.
Thus, the number of individuals included in the summary is 146.