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zalisa [80]
3 years ago
15

The Drama Club sold 450 tickets for the spring play. An adult ticket cost $5 and a student ticket cost $3. Total ticket sales eq

ualed $1900. Find out how many adult and student tickets the club sold.
Mathematics
1 answer:
Reil [10]3 years ago
4 0
x+y=450
5x+3y=1900


x=450-y
5(450-y)+3y=1900

-2y+2250=1900
-2y=-350
y=175
x=275
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A pharmacist receives a shipment of 21 bottles of a drug and has three of the bottles tested. If five of the 21 bottles are cont
blagie [28]

Answer:

The probability is 0.8722

Step-by-step explanation:

There are 21 bottles

5 of them are contaminated.

there are 21 - 5 = 16 non-contaminated bottles.

So, if we grab a bottle at random, the probability that this bottle is contaminated will be equal to the quotient between the number of contaminated bottles and the total number of bottles, this is:

p = 5/21

Now we want to find the probability that, for 3 tested bottles, that less than two (0 or 1 ) are contaminated.

Let's see each case on its own.

0 bottles:

The probability of getting a non-contaminated bottle in the first try is equal to the quotient between the number of non-contaminated bottles and the total number of bottles, this is:

p₁ = 16/21

For the second bottle is the same, but because one non-contaminated bottle was drawn before, now there are 15 non-contaminated bottles and 20 bottles in total, so now the probability is:

p₂ = 15/20

and similarly, for the third bottle the probability is:

p₃ = 14/19

The joint probability is the product of the individual probabilities, we get:

P = p₁*p₂*p₃ = (16/21)*(15/20)*(14/19) = 0.4211

Now the case that one bottle is contaminated.

Let's assume that the first one is contaminated.

The probability of getting a contaminated bottle in the first draw is equal to the quotient between the number of contaminated bottles and the total number of bottles, so:

p₁ = 5/21

For the second bottle, we want a non-contaminated one, there are 16 non-contaminated bottles and 20 bottles left, so here the probability is:

p₂ = 16/20

and for the third bottle we have the probability:

p₃ = 15/19

The joint probability is:

p = p₁*p₂*p₃ = (5/21)*(16/20)*(15/19)

Also notice that we only looked at the case where the first bottle is contaminated, we also have the case where the second one is contaminated and the case where the third one is  contaminated, so there are 3 permutations, then the probability of having one contaminated bottle is:

Q = 3*p = 3*(5/21)*(16/20)*(15/19) = 0.4511

Then the probability of having less than two contaminated bottles is:

probability = P + Q = 0.4211 + 0.4511 = 0.8722

8 0
2 years ago
Gavin drove 85 miles on 10 gallons of gas. How many miles can Gavin drive on 25 gallons of gas?
Setler79 [48]
212.5 miles because Gavin drives 85 miles on 10 gallons therefore 85/10=8.5 miles per gallon X 25 gallons=212.5
5 0
3 years ago
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Karolina [17]
4s-3s=2 and if you were to solve this you would combine the s and get 1s so 1s=2
7 0
3 years ago
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Mr. Smith offered to stay after school for an extra help session. The day after the
marissa [1.9K]

Answer:

132 students

Step-by-step explanation:

Mr Smith offers to take extra help session for students after school

The day after the help session 11 of his students were talking and found out that only 2 had stayed up for the help session

= 2/11

There were actually a total number of 24 students that stayed

We are asked to find the number of student that Mr Smith teaches throughout the day

Let x represent the number of students that were taught during the day

Therefore, the number of student that Mr Smith teaches during the day can be calculated as follows

2/11=24/x

Cross multiply both sides

2 × x = 24 × 11

2x= 264

Divide both sides by 2

2x/2=264/2

x= 132

Hence Mr Smith teaches 132 students during the day.

7 0
3 years ago
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marysya [2.9K]

Answer:

54

Step-by-step explanation:

Multiply:

<em>37x37=72</em>

<em>Subtract:</em>

<em>180-72=108</em>

<em>Divide:</em>

<em>108/2=54</em>

6 0
2 years ago
Read 2 more answers
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