Maths hw???????please help^^^^^^^^

Stolb23 [73]

Answer:

here's a link to help as well

Step-by-step explanation:

https://www.prodigygame.com/blog/distributive-property/#exponents

Expand the equation.

Multiply (distribute) the first numbers of each set, outer numbers of each set, inner numbers of each set, and the last numbers of each set.

Combine like terms.

Solve the equation and simplify, if needed.

3 0

3 years ago

You just received an insurance settlement offer related to an accident you had six years ago. The offer gives you a choice of on

Usimov [2.4K]

answer:

Step-by-step explanation:

Option A. $1565 for 72months

Then the total is $112,680

Option B. $1012 for a month for 10 years,

10years is equivalent to 120months

Therefore, the total income is 1012×120

$121,440.

Option 3.

$100,000 once payment.

All the information is correct.

But,

Since the individual did not care if he receives the fund or it is transfer to his heir, so we can ignore the third option of collecting $100000 lump sum.

Also, since he is also ready to wait and he is indifferent about who earns the insurance settlement so he can as well wait and ignore the 72months.

So he can go for the second option because it pays the largest amount and he will receive the most payments.

He will receive $121,440 if he waits for ten years.

4 0

4 years ago

Hue is arranging chairs. She can form 5 rows of a given length with 2 chairs left over, or 7 rows of that same length if she get

Andru [333]

I just took the 16 chairs and added 2 since thats how many are left over, then since adding these 16 chairs, you are creating 2 more rows, so (16+2)/2 =9 Therefore, each row must have nine chairs in it and Hue starts off with 5x9+2= 47 chairs

4 0

3 years ago

(a) The perimeter of a rectangular field is 276 m.

Deffense [45]

Answer:

(a) 63 (b) 99

Step-by-step explanation:

(a)

length x 2 = 150

275-150=126/2= 63

(b)

8712/88= 99

4 0

3 years ago

Suppose a professional golfing association requires that the standard deviation of the diameter of a golf ball be less than 0.00

Bingel [31]

Answer:

We conclude that the standard deviation of the diameter of a golf ball is less than 0.005 inch.

Step-by-step explanation:

We are given that a professional golfing association requires that the standard deviation of the diameter of a golf ball be less than 0.005 inch.

Assume that the population is normally distributed: 1.678, 1.681, 1.676, 1.684, 1.676, 1.679, 1.681, 1.681, 1.677, 1.676, 1.681, 1.683.

Let $\sigma$ = population standard deviation of the diameter of a golf ball.

SO, Null Hypothesis, $H_0$ : $\sigma \geq$ 0.005 inch {means that the standard deviation of the diameter of a golf ball is more than or equal to 0.005 inch}

Alternate Hypothesis, $H_0$ : $\sigma$ < 0.005 inch {means that the standard deviation of the diameter of a golf ball is less than 0.005 inch}

The test statistics that would be used here One-sample Chi-square test statistics;

T.S. = $\frac{(n-1)s^{2} }{{\sigma^{2} }}$ ~ $\chi^{2} __n_-_1$

where, s = sample standard deviation = $\sqrt{\frac{\sum (X-\bar X)^{2} }{n-1} }$ = 0.00281 inch

n = sample size = 12

So, the test statistics = $\frac{(12-1)\times 0.00281^{2} }{{0.005^{2} }}$ ~ $\chi^{2} __1_1$

= 3.47

The value of chi-square test statistics is 3.47.

Also, the P-value of test statistics is given by the following formula;

P-value = P( $\chi^{2} __1_1$ < 3.47) = 0.0182

Since, the P-value of the test statistics is less than the level of significance as 0.0182 < 0.05, so we reject our null hypothesis.

Now, at 0.05 significance level the chi-square table gives critical value of 4.575 at 11 degree of freedom for left-tailed test.

Since our test statistic is less than the critical value of chi-square as 3.47 < 4.575, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that the standard deviation of the diameter of a golf ball is less than 0.005 inch.

7 0

3 years ago