Maths hw???????please help^^^^^^^^

Mathematics

1 answer:

belka [17]3 years ago

7 0

6(2x+1) ≤ 5x-1
Distribute
12x+6 ≤ 5x-1
-5x -5x

7x+6 ≤ -1
-6 -6

7x ≤ -7
/7 /7

x ≤ -1

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3. Vocabulary Suppose △MNP ∼△RST. How can you identify corresponding parts?

MakcuM [25]

Similar triangles may or may not have congruent sides, but the ratio of the corresponding sides will always be congruent.

(3) Corresponding sides of △MNP and △RST

Given that △MNP ∼△RST.

This means that, the corresponding sides are:

MN and RS
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(4) The equal measures

Given that △ABC ∼△TUV

This means that, the corresponding angles are equal, but corresponding sides are not.

So, the equal measures are:

(a). the measures of ∠A and ∠T
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The unequal measure is:

(b). the perimeters of the two triangles

(c) Scale mapping

The scale mapping is given as:

$Ratio = 1\ in : 100\ mi$

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500 is 5 times 100

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Read more about similar triangles at:

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3 years ago

How do you write a polynomial function for this graph?

expeople1 [14]

first off, let's notice the graph touches the x-axis at -1 and 3, namely, those are the zeros/solutions/roots of the polynomial and therefore, the factors come from those points.

now, at -1, the graph doesn't cross the x-axis, instead it simply bounces off of it, that means the zero of x = -1, has an even multiplicity, could be 4 or 2 or 6, but let's go with 2.

at x = 3, the graph does cross the x-axis, meaning it has an odd multiplicity, could be 3 or 1, or 7 or 9, but let's use 1.

$\bf \begin{cases} x=-1\implies &x+1=0\\ x=3\implies &x-3=0 \end{cases}~\hspace{5em}\stackrel{\textit{even multiplicity}}{(x+1)^2}\qquad \stackrel{\textit{odd multiplicity}}{(x-3)^1}=\stackrel{y}{0} \\\\\\ (x^2+2x+1)(x-3)=y\implies x^3+2x^2+x-3x^2-6x-3=y \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill x^3-x^2-5x-3=y~\hfill$