For the pair of compound Fe(s) or CCl4(s) the one with the higher melting point is For the pair of compound F e ( s ) or C C l 4
( s ) the one with the higher melting point is blank.. For the pair of compound KCl(s) or HCl(s) the one with the higher melting point is For the pair of compound K C l ( s ) or H C l ( s ) the one with the higher melting point is blank.. For the pair of compound H2O(s) or H2S(s) the one with the higher melting point is For the pair of compound H 2 O ( s ) or H 2 S ( s ) the one with the higher melting point is blank.. For the pair of compound Ti(s) or Ne(s) the one with the higher melting point is___________.
The bonding in molecules or compounds will determine its boiling or melting point. The stronger the bonds between the compound and molecules, the higher the energy needed to break the bonds which leads to an higher boiling or melting point.
Fe (Iron) has an higher melting point than CCl4 (Tetrachloromethane). The bonding in Fe is metallic while CCl4 has van der waal force. Metallic bonding is stronger than van der waal force. Much energy is needed to break metallic bonding compared to van der waal force
KCl (potassium chloride)has ionic bonding while HCl (hydrochloric acid) has permanent dipole (covalent bonding). Ionic bonding is stronger than any covalent bonds. Therefore KCl will have a higher melting point than HCl
H20 (water) has hydrogen bonding while H2S (hydrogen sulpide) has permanent dipole. Hydrogen bonding is stronger than permanent dipole.
Ti (Titanium) has a metal having metallic bonding while Ne (neon) has van der waal forces. metallic bonding is stronger than van der waal forces.
Glycosidic bonds in starch and ester bonds in triglycerides. The glycosidic bond is considered to be the covalent synthetic bonds that connection ring-molded sugar particles to different atoms. The frame by a buildup response between a liquor or amine of one particle and the anomeric carbon of the sugar, and hence, might be O-connected or N-connected.
Inside the nucleus, the attractive strong nuclear force between protons outweighs the repulsive electromagnetic force and keeps the nucleus stable. Outside the nucleus, the electromagnetic force is stronger and protons repel each other.
