The answer is C. 146g because you add all of the masses of the individual elements and then mulyiply by 1.72 to get your answer.
Answer: option b. Neutral organic compounds
Explanation:
Answer:
message me so i can help you because i cant see the words
Explanation:
A) mass / volume = density
m/6.00cm3 = 13.5939g/cm3
m = 13.5939g/cm3 • 6.00cm3
m = 81.6g
B) mass / volume = density
m/25.0cm3 = 0.702g/cm3
m = 0.702cm3 • 25.0g/cm3
m = 17.6g
1mL = 1cm3
<span>First - you need the empirical formula.
So, assume you have 100 g of the compound.
If so, you'll have 54.53 gram of C, 9.15 g of H and 36.32 g of O. Find the number of moles of each.
54.53 g C (1 mole C / 12.01 g C) = 4.540
9.15 g H (1 mole H / 1.008 g H) = 9.077
36.32 g O (1 mole O / 15.9994 g O) = 2.270
Take the smallest number found and divide the others by it to get the empirical formula.
4.540/2.270 = 2.
9.077/2.270 = 4.
2.270/2.270 =1.
So, that gives you the empirical formula of C2H4O.
Find the weight of this compound. C = 12, H = 1, O = 16. So, C2H4O is 44 amu.
132/44 = 3.
So, 3 (C2 H4 O) = C6H12O3 = molecular formula.</span>