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cricket20 [7]
3 years ago
13

GUYS I REALLY NEED THIS ASAP!!!!!​

Chemistry
1 answer:
Nastasia [14]3 years ago
8 0

Answer:

I don't think so

Explanation:

The equation doesn't look balanced

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The half-life of radium-226 is 1590 years. if a sample contains 100 mg, how many mg will remain after 1000 years?
AlladinOne [14]

Answer:

64.52 mg.

Explanation:

The following data were obtained from the question:

Half life (t½) = 1590 years

Initial amount (N₀) = 100 mg

Time (t) = 1000 years.

Final amount (N) =.?

Next, we shall determine the rate constant (K).

This is illustrated below:

Half life (t½) = 1590 years

Rate/decay constant (K) =?

K = 0.693 / t½

K = 0.693/1590

K = 4.36×10¯⁴ / year.

Finally, we shall determine the amount that will remain after 1000 years as follow:

Half life (t½) = 1590 years

Initial amount (N₀) = 100 mg

Time (t) = 1000 years.

Rate constant = 4.36×10¯⁴ / year.

Final amount (N) =.?

Log (N₀/N) = kt/2.3

Log (100/N) = 4.36×10¯⁴ × 1000/2.3

Log (100/N) = 0.436/2.3

Log (100/N) = 0.1896

Take the antilog

100/N = antilog (0.1896)

100/N = 1.55

Cross multiply

N x 1.55 = 100

Divide both side by 1.55

N = 100/1.55

N = 64.52 mg

Therefore, the amount that remained after 1000 years is 64.52 mg

7 0
3 years ago
Which results when an atom has such a strong attraction for electrons that it pulls one or more electrons completely away from a
IgorLugansk [536]

<em><u>All people are tax people</u></em>

-Turbo tax

4 0
3 years ago
A tree trunk floating in the water<br> Balanced<br> Or<br> Unbalanced
mars1129 [50]

Answer:

Balanced

Explanation:

Please help me by marking me brainliest. I'm one away :)

3 0
3 years ago
at stp which of following would have the same number of molecules a 1 l of c2h4 gas? a. 0.5 of H2 b. 1L of Ne c.2L of H2O d.3L o
sashaice [31]

Answer:d

Explanation:

4 0
3 years ago
The different molecules that make up the air in a room have on average the same kinetic energy. How does the speed of the differ
kap26 [50]
The formula for kinetic energy is KE=1/2(mv²).  Since both mass and velocity are multiplied by each other, particle with a larger mass needs to be moving slower than a particle with less mass if both have the same kinetic energy. You can think of it as 2KE/m=v² or 2KE/v²=m, If you increase the mass the velocity needs to decrease to keep the same KE value.

I hope this helps.  Let me know in the comments if anything is unclear.
7 0
3 years ago
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