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2 years ago

3) What is the new strategy for disposing of nuclear waste? How is this strategy still dangerous?

Chemistry

1 answer:

kumpel [21]2 years ago

4 0

Answer:

the newest strategy on get hurt a nuclear warhead we store any chemical agents is to actually dispose of them area of water lighten them off where there is no land animals or any other living breathing animals mammals plantations therefore the correct waste should be disposed of properly by either nuking it in like a loner thing when we burn bodies or in an isolated area where it cannot harm fellow American people animals tree life they should be disposed of properly properly by scientists that have corrected it and know how to break it down there for non giving harmful bacteria land my phone is going to die over Zone and taking away our atmosphere

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Explain what the atomic number and atomic mass of an element represent. use an example of an element. describe how the atomic nu

Lapatulllka [165]

The atomic number is how many protons are in the nucleus of the atom. The atomic mass is how much mass is in the atom. Example: The atomic number of Helium is 2, and the atomic mass is 4. To calculate the atomic number, simply count the protons. To calculate the atomic mass of an atom, add up the mass of protons and neutrons. Hope this helped! c:

8 0

3 years ago

If 52.5 mL of lead(II) nitrate solution reacts completely with excess sodium iodide solution to yield 0.248 g of precipitate, wh

user100 [1]

Explanation:

The volume of given lead nitrate solution is:

52.5 mL.

The amount of lead iodide formed is ---0.248 g.

To get the molarity of lead (II) ion follow the below-shown procedure:

The number of moles of lead iodide formed is:

$number of moles of lead iodide(n)=mass of lead iodide/its molecular mass\\n=0.248 g/461.01g/mol\\n=0.000537mol$

0.000537 mole of lead iodide contains --- 0.000537 moles of lead (II) ion.

Thus, the number of moles are there, volume is there, and to get the molarity of lead (II) ion use the formula:

$Molarity=\frac{number of moles}{volume in L.} \\M=0.000537 mol / 0.0525 L.\\M=0.0102mol/L$

Molarity of lead iodide is --- 0.0102 M.

7 0

3 years ago

Can someone answer these for me I’ll mark you brainliset or whatever it’s called lol I rlly need to get these right

aleksandrvk [35]

Gg rjhrrjfnrjrkrkrkrjjtjrrkrktotofofovkfjiffiifi

7 0

2 years ago

What volume of oxygen in liters at STP wpuld be required for the combustion of 17.0 grams PH3?

Lynna [10]

First, we need to state the chemical equation for the combustion of PH3

$4PH3\text{ + 8O2 }\to\text{ P4O10 }+6H2O$

And the mass of PH3 is 17.0 grams and we need to know the moles.

In the periodic table, the atomic mass of the P (phosphorus) is 31 and the atomic mass of the H (hydrogen) is 1.

So, you sum the mass of P to the mass of H multiplied by 3 and you obtain this:

$\text{mole}cu\text{lar weight of PH3=31}\cdot1+1\cdot3=34\text{ g PH3/mol}$

With this data, we can search the moles of PH3:

7 0

10 months ago

A compound is found to contain 26.73 % phosphorus, 12.09 % nitrogen, and 61.18 % chlorine by mass. What is the empirical formula

Mrrafil [7]

Answer:

$PNCl_2$

Explanation:

Hello!

In this case, when determining empirical formulas by knowing the by-mass percent, we first must assume the percentages as masses so we can compute the moles of each element:

$n_P=\frac{26.73g}{30.97g/mol}=0.863mol\\\\n_N=\frac{12.09g}{14.01g/mol}=0.863mol\\\\n_C_l=\frac{61.18g}{35.45g/mol}=1.726mol$

Now, for the determination of the subscript of each element in the empirical formula, we divide the moles by the fewest moles (P or N):

$P=\frac{0.863mol}{0.863mol}=1\\\\N= \frac{0.863mol}{0.863mol}=1\\\\Cl=\frac{1.726mol}{0.863mol}2$

Thus, the empirical formula is:

$PNCl_2$

Regards!

4 0

2 years ago