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3 years ago

13

The main target when controlling the acidity of soils is ______. a. neutralizing the pH b. adding base c. replacing lost cation

nutrients d. eliminating humic acids Please select the best answer from the choices provided A B C D

2 answers:

V125BC [204]3 years ago

7 0

Answer:

C

Explanation:

Phoenix [80]3 years ago

6 0

Answer:

The answer is C

Explanation:

Just took the test

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Thermal energy is a form of

Mrrafil [7]

Thermal energy is an example of kinetic energy, as it is due to the motion of particles, with motion being the key. Thermal energy results in an object or a system having a temperature that can be measured. Thermal energy can be transferred from one object or system to another in the form of heat. hope this helps

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4 years ago

Read 2 more answers

A. Gallium is produced by the electrolysis of a solution obtained by dissolving gallium oxide in concentrated NaOH(aq). Calculat

liraira [26]

Answer:

A)Mass of gallium plated out is 0.3440 grams

B) For 0.67 hours current of 5.79 A must to be applied to plate out 8.70 g of tin.

Explanation:

To calculate the total charge, we use the equation:

$C=I\times t$

where,

C = Charge

I = Current in time t (seconds)

To calculate the moles of electrons, we use the equation:

$\text{Moles of electrons}=\frac{C}{F}$

where,

F = Faraday's constant = 96500

A) The equation for the deposition of Ga(s) from Ga(III) solution follows:

$Ga^{3+}(aq.)+3e^-\rightarrow Ga(s)$

I = 0.790 A, t = 30.0 min = 1800 seconds

$C=I\times t$

$C=0.790 A\times 1800 s=1422 C$

Moles of electron transferred:

$=\frac{1422 C}{96500 F}=0.01474 mol$

Now, to calculate the moles of gallium, we use the equation:

$\text{Moles of Gallium}=\frac{\text{Moles of electrons}}{n}$

n = number of electrons transferred = 3

$\text{Moles of Gallium}=\frac{0.01474 mol}{3}=0.004913 mol$

Mass of 0.004913 moles of gallium = 0.004913 mol × 70 g/mol=0.3440 g

B) The equation for the deposition of Sn(s) from Sn(II) solution follows:

$Sn^{2+}(aq.)+2e^-\rightarrow Sn(s)$

Moles of tin = $\frac{8.70 g}{119 g/mol}=0.07311 mol$

n = number of electrons transferred = 2

$\text{Moles of tin}=\frac{\text{Moles of electrons}}{n}$

Moles of electron = $n\times \text{Moles of tin}$

$=2\times 0.07311 mol=0.14622 mol$

Charge transferred during time t :

$\text{Moles of electrons}=\frac{C}{F}$

$C=96500 F\times 0.14622 mol=14,110.23 C$

Current applied for t time = I = 5.79 A

$t=\frac{C}{I}=\frac{14,110.23 C}{5.79 A}=2,437 s=0.67 hrs$

For 0.67 hours current of 5.79 A must to be applied to plate out 8.70 g of tin.

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4 years ago

31,32<br> show work plz and help asap

Yakvenalex [24]

Answer: 31 (a) 4 32 (a) 5

(b) 7 (b) 3

(c) 5 (c) 5

(d) 3 (d) 2

<u>Significant Figures (sf) Rules:</u>

1) Trailing zeroes are considered significant ONLY If a decimal point is provided.

2) Zeroes between the decimal point and number are NOT significant <u>unless</u> they are between numbers.

3) All digits in scientific notation are counted (disregard the exponent).

31 (a) 508.0 <em>trailing zero so use rule 1 </em> --> sf = 4

(b) 820,400.0 <em>trailing zero so use rule 1 </em> --> sf = 7

(c) 1.0200 x 10⁵ <em>scientific notation so use rule 3</em> --> sf = 5

(d) 807,000 <em>no trailing zeroes so use rule 1</em> --> sf = 3

32 (a) 0.049450 <em>zero between decimal point & #, use rule 2</em> --> sf = 5

(b) 0.000482 <em>zero between decimal point & #, use rule 2</em> --> sf = 3

(c) 3.1587 x 10 ⁻⁸ <em>scientific notation so use rule 3</em> --> sf = 5

(d) 0.0084 <em>zero between decimal point & #, use rule 2</em> --> sf = 2

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4 years ago

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Digiron [165]

Sorry I need the points

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3 years ago

Why are mixtures important in our daily lives

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It depends on what types of mixtures you're talking about

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