What volume in milliliters of 0.0150 M Ba(OH)2 is required to neutralize 50.0 mL of 0.0500 M HBr?
1 answer:
The volume of required will be 83.33 mL
The equation of the reaction is as follows:
Mole ratio of reactants = 1:2
Mole of 50 mL, 0.05 M HBr = 0.05 x 0.05 = 0.0025 moles
Equivalent mole of = 0.0025/2 = 0.00125 moles
Volume of 0.015 M, 0.00125 moles = 0.00125/0.015 = 0.0833 L
0.0833 L = 83.33 mL
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Answer:
p-fluoronitrobenzene and sodium phenoxide is more appropriate
Explanation:
An ipso substitution is required to form p-nitrophenyl phenyl ether.
For this ipso substitution, an alkoxide anion needs to attack as a nucleophile at the carbon atom attached to fluorine atom and thereby substitute that F atom.
p-nitrophenoxide is an weak nucleophile as compared to phenoxide due to presence of electron withdrawing resonating effect of nitro group at para position.
p-fluoronitrobenzene is a good choice for nucleophilic attack by alkoxide anion as compared to fluorobenzene due to higher positive charge density at carbon atom directly attached to F atom. Higher positive charge density arises due to presence of electron withdrawing resonating effect og nitro group at para position.
So, p-fluoronitrobenzene and sodium phenoxide is more appropriate
