Answer:
(0.63789 ; 1.38211 )
Given that:
Mean, xbar = 1.01
Standard deviation, s = 0.29
Sample size, n = 7
Confidence interval : xbar ± margin of error
Margin of Error = Tcritical * s/sqrt(n)
Degree of freedom (df) = n - 1 = 7 - 1 = 6
Hence Tcritical = 3.143
Margin of Error = 3.143 * 0.29/sqrt(6)
Margin of error = 0.37211
Lower boundary = (1.01 - 0.37211) = 0.63789
Upper boundary = (1.01 + 0.37211) = 1.38211
(0.63789 ; 1.38211 )
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<span>System 1 and system 2, because the second equation in system 2 is obtained by adding the first equation in system 1 to two times the second equation in system 1
This is the correct answer because not only is it true but it also follows the property of solving systems of equations with adding the equations. To prove that it is true:
2nd equation in system #2 = 1st equation in system #1 + 2(2nd equation in system #1)
</span>10x − 7y = 18 == 4x − 5y = 2 + 2(<span>3x − y = 8)
10x - 7y = 18 == 4x - 5y = 2 + 6x - 2y = 16
10x = 7y = 18 == 10x - 7y = 18</span>
Answer:
Distance between points (5, -3) and (0, 2) is √50 or 7.07
Step-by-step explanation:
We need to find distance between two points (5,-3) and (0,2)
The distance formula used is:
here
x₁= 5, y₁=-3, x₂=0 and y₂=2
Putting values in the formula:
So, distance between points (5, -3) and (0, 2) is √50 or 7.07
1. Given that e<span>vents A and B are dependent, P(A)=20%, P(BIA)=25%. What is P(A and B)?
P(BIA)=[P(A and B)]/P(A)
it follows then that:
P(A and B)=P(A)*P(BIA)
P(A)=0.2
P(BIA)=0.25
hence
P(A and B)=0.2*0.25=0.05=5%
2. Given that </span><span> P(A) =12%, P(B)=48% and P(A or B)=50%. What is P(A and B)?
P(A or B)=P(A)+P(B)-P(A and B)
but
P(A)=12%, P(B)=48%, P(A and B)=50%
thus
P(A or B)=12%+48%-50%
simplifying the above we obtain:
P(A or B)=60%-50%=10%
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