<span>Poet Kuangchi Chang did not remain in China long enough to be "re-educated." Following the Communist takeover he fled to the United States. His poem "Garden of My Childhood" describes China before the revolution as a peaceful, idyllic garden with a violent horde rapidly approaching. A vine, the wind, and the sea are each personified, and each beckons for him to run. It is not until "eons later," when he is "worlds away," that his "running is all done," and he finds himself at his destination: another garden, just like the one he had left behind.</span>
Answer:
El trabajo realizado para subir los últimos 500 metros es 318727,5 joules.
Explanation:
Por la definición de trabajo sabemos que el montañero debió contrarrestar trabajo causado por la gravedad terrestre. Si asumimos que el cambio de la altura es muy pequeño en comparación con el radio del planeta (6371 kilómetros vs. 0,5 kilómetros), entonces podemos considerar que la aceleración gravitacional es constante y la ecuación de trabajo (
), medido en joules, que reducida a:
(1)
Donde:
- Masa del montañero, medido en kilogramos.
- Aceleración gravitacional, medida en metros por segundo al cuadrado.
- Distancia vertical de ascenso del montañero, medida en metros.
Si tenemos que
,
y
, entonces el trabajo realizado por el montañero para subir es:
![\Delta W = (65\,kg)\cdot \left(9,807\,\frac{m}{s^{2}} \right)\cdot (500\,m)](https://tex.z-dn.net/?f=%5CDelta%20W%20%3D%20%2865%5C%2Ckg%29%5Ccdot%20%5Cleft%289%2C807%5C%2C%5Cfrac%7Bm%7D%7Bs%5E%7B2%7D%7D%20%5Cright%29%5Ccdot%20%28500%5C%2Cm%29)
![\Delta W = 318727,5\,J](https://tex.z-dn.net/?f=%5CDelta%20W%20%3D%20318727%2C5%5C%2CJ)
El trabajo realizado para subir los últimos 500 metros es 318727,5 joules.
Answer:
Circular motion: find period, find radius, find velocity, find centripetal acceleration 27 V= T a =vºlr=rw
Explanation:
Answer: you subtract the number of protons from the mass number, on the periodic table your atomic number is your protons and your atomic mass is the mass number
Explanation:
Hello! Assuming that the only force acting on the mass is 30N...
Fnet = 30N
Fnet = ma (mass x acceleration)
ma = 30N
a = 30N / m
a = 30N / 7kg
a = 4.2857 m/s^2
a = 4 m/s^2
I hope this helps!