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Murljashka [212]
2 years ago
13

What object requires less force to overcome inertia B.80 kg piece of furniture or A.1000 kg vehicle

Physics
1 answer:
Tju [1.3M]2 years ago
8 0

Less force will be necessary to overcome inertia for the 80 kg piece of furniture.

Force is a factor that has the power to alter an object's motion. A massed object's velocity can be changed or accelerated by a force. A push or a pull is a straightforward method to explain forces.

The term "moment of inertia" refers to the quantity that describes how a body resists angular acceleration and is calculated by multiplying each particle's mass by its square of the distance from the rotational axis.

I = mr², where m is the mass of the object and r is the distance to the rotation axis.

Therefore, The inertia is directly proportional to the mass of the object.

So, as the mass increases the inertia increases.

Therefore, 80 kg piece of furniture will require less force to overcome inertia.

Learn more about inertia here:

brainly.com/question/14460640

#SPJ9

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lyudmila [28]
This link should help you out https://quizlet.com/40330134/biomechanics-questions-flash-cards/
7 0
3 years ago
A series circuit that is connected to a 50 V, 60 Hz source is made up of 25 ohm resistor, capacite wieh X= 18 ohms, and inductor
Allisa [31]

Answer:

the impedance of the circuit is 25.7 ohms.

Explanation:

It is given that,

Voltage, V = 50 volts

Frequency, f = 60 Hz

Resistance, R = 25 ohms

Capacitive resistance, X_C=18\ ohms

Inductive resistance, X_L=24\ ohms

We need to find the impedance of the circuit. It is given by :

Z=\sqrt{R^2+(X_L-X_C)^2}

Z=\sqrt{25^2+(24-18)^2}

Z = 25.7 ohms

So, the impedance of the circuit is 25.7 ohms. Hence, this is the required solution.

6 0
3 years ago
When you push on an object such as a wrench, a steel pry bar, or even the outer edge of a door, you produce a torque equal to th
Korvikt [17]
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5 0
3 years ago
A wheel accelerates from rest to 34.7 rad/s at a rate of 47.0 rad/s^2. Through what angle (in radians) did the wheel turn while
dem82 [27]

12.8 rad

Explanation:

The angular displacement \theta through which the wheel turned can be determined from the equation below:

\omega^2 = \omega_0^2 + 2\alpha\theta (1)

where

\omega_0 = 0

\omega = 34.7\:\text{rad/s}

\alpha = 47.0\:\text{rad/s}^2

Using these values, we can solve for \theta from Eqn(1) as follows:

2\alpha\theta = \omega^2 - \omega_0^2

or

\theta = \dfrac{\omega^2 - \omega_0^2}{2\alpha}

\:\:\:\:= \dfrac{(34.7\:\text{rad/s})^2 - 0}{2(47.0\:\text{rad/s}^2)}

\:\:\:\:= 12.8\:\text{rad}

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Answer:

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