Answer: The diameter of the circular path is 2.96m
Explanation: centripetal acceleration = tangential speed^2 / radius of the circular path.
Centripetal acceleration = 2.7m/s^2
Tangential speed = 2.0m/s
Radius = 2.0^2 / 2.7 = 4/2.7
= 1.48m
Diameter = radius*2
= 1.48*2 = 2.96m.
I'll be happy to solve the problem using the information that
you gave in the question, but I have to tell you that this wave
is not infrared light.
If it was a wave of infrared, then its speed would be close
to 300,000,000 m/s, not 6 m/s, and its wavelength would be
less than 0.001 meter, not 12 meters.
For the wave you described . . .
Frequency = (speed) / (wavelength)
= (6 m/s) / (12 m)
= 0.5 / sec
= 0.5 Hz .
(If it were an infrared wave, then its frequency would be
greater than 300,000,000,000 Hz.)
Answer:
it is ---D because you can't measure gas and it's mass
HOPE THIS HELPS
Answer: 1 The correct answer is that CMB radiation was spread uniformly throughout the whole universe.This was related to big band theory because this theory predicts that the universe was a very hot place and as it cooled down it should have been filled with laterally the remnant heat over from the Big Bang called as cosmic microwave background.
Answer: 2 CMB radiation was discovered accidentally when Penzias and Wilson were performing some experiment and they noticed a ' hum' noise that was constantly detected by the antenna even after removing all the disturbing sources.
Then it was realized that it is cosmic microwave background radiation.
<span>3.36x10^5 Pascals
The ideal gas law is
PV=nRT
where
P = Pressure
V = Volume
n = number of moles of gas particles
R = Ideal gas constant
T = Absolute temperature
Since n and R will remain constant, let's divide both sides of the equation by T, getting
PV=nRT
PV/T=nR
Since the initial value of PV/T will be equal to the final value of PV/T let's set them equal to each other with the equation
P1V1/T1 = P2V2/T2
where
P1, V1, T1 = Initial pressure, volume, temperature
P2, V2, T2 = Final pressure, volume, temperature
Now convert the temperatures to absolute temperature by adding 273.15 to both of them.
T1 = 27 + 273.15 = 300.15
T2 = 157 + 273.15 = 430.15
Substitute the known values into the equation
1.5E5*0.75/300.15 = P2*0.48/430.15
And solve for P2
1.5E5*0.75/300.15 = P2*0.48/430.15
430.15 * 1.5E5*0.75/300.15 = P2*0.48
64522500*0.75/300.15 = P2*0.48
48391875/300.15 = P2*0.48
161225.6372 = P2*0.48
161225.6372/0.48 = P2
335886.7441 = P2
Rounding to 3 significant figures gives 3.36x10^5 Pascals.
(technically, I should round to 2 significant figures for the result of 3.4x10^5 Pascals, but given the precision of the volumes, I suspect that the extra 0 in the initial pressure was accidentally omitted. It should have been 1.50e5 instead of 1.5e5).</span>
