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Elden [556K]
3 years ago
12

Answer plzandfollow me​ ​

Physics
2 answers:
andrew-mc [135]3 years ago
6 0

Answer:

80m

Explanation:

s =1/2(a+b)h

=1/2(6+10)×10

=1/2×16×10

=8×10

=80m

Goodluck

JulijaS [17]3 years ago
6 0

Answer:

Explanation:

To determine the displacement under the velocity-time graph, we explore the area of the:

(1) region of acceleration

(2) region of constant velocity

(3) area of region of deceleration

so to couple this up, we explore the area of a trapezium

height = 10

a = length BC = 8 - 2 = 6

b = 10

Area of a trapezium = 1/2(a + b)*h = 1/2(6 + 10)*10 =8*10 = 80m

The displacement = 80m

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Question 8: Cosmology (8 points)
STatiana [176]

Big bang happened about 13.7 billion years ago in our universe.

<h3>Describe the beginning of the universe according to the big bang theory?</h3>

According to the big bang theory, about 13.7 billion years ago, an explosive expansion began, expanding our universe outwards faster than the speed of light.

<h3>Describe the future of the universe according to the flat model?</h3>

According to the flat model, the universe is infinite and will continue to expand forever because the universe is expanding.

<h3>What is cosmic background radiation? </h3>

Cosmic background radiation is a weak radio-frequency radiation that is traveling through outer space in every direction. It is the residual radiation of the big bang, when the universe was very hot.

<h3>How do observations of the cosmic background radiation provide evidence to support the big bang theory? </h3>

The Big Bang theory predicts that the early universe was a very hot place and that as it expands, the gas within it cools. Thus the universe has all over radiation which is called the “cosmic microwave background".

Learn more about big bang here: brainly.com/question/10865002

#SPJ1

6 0
2 years ago
A train travels a distance of 2000 km at an average speed of 120 km per hour. How long did the trip take? SHOW WORK
Igoryamba
S = d/t, s = 120, d = 2000, t = ?
Input the values,
120 = 2000/t
Make t the subject of the formula by cross multiplying, Therefore,
120t = 2000
Divide both sides by 120
t = 16.7hrs  to 1 decimal place.
If you're asked to convert it, you can.


6 0
3 years ago
The graph at the right shows the force needed to pull a bow back as the string is pulled further and further.
Sindrei [870]

A. 9 J

In a force-distance graph, the work done is equal to the area under the curve in the graph.

In this case, we need to extrapolate the value of the force when the distance is x=30 cm. We can easily do that by noticing that there is a direct proportionality between the force and the distance:

F=kx

where k is the slope of the line. We can find k, for instance chosing the point at x=5 cm and F=10 N:

k=\frac{F}{x}=\frac{10 N}{5 cm}=2 N/cm

And now we can calculate the work by calculating the area under the curve until x=30 cm, F=60 N:

W=\frac{1}{2} (height) (base)= \frac{1}{2}(60 N)(0.30 m)=9 J


B. 24.5 m/s

The mass of the arrow is m=30 g=0.03 kg. The kinetic energy of the arrow when it is released is equal to the work done by pulling back the bow for 30 cm:

W=K=\frac{1}{2}mv^2

where m is the mass of the arrow and v is its speed. By re-arranging the formula and using W=9 J, we find the speed:

v=\sqrt{\frac{2W}{m}}=\sqrt{\frac{2\cdot 9J}{0.03 kg}}=24.5 m/s

8 0
3 years ago
Free charges do not remain stationary when close together. To illustrate this, calculate the magnitude of the instantaneous acce
ASHA 777 [7]

Answer:

a=2.304×10¹⁶m/s²

Explanation:

Given data

Distance d=2.5 nm=2,5×10⁻⁹m

Mass of proton m=1.6×10⁻²⁷kg

charge of proton q=1.6×10⁻¹⁹C

To find

acceleration a

Solution

Apply the Coulombs Law

F=k\frac{q_{1}q_{2}  }{r^{2} }

Where k is coulombs constant (k=9×10⁹Nm²/C²)

q=q₁=q₂

r=d

So

F=k\frac{|q^{2} |}{d^{2} }\\ as \\F=ma\\ma=k\frac{|q^{2} |}{d^{2} }\\a=\frac{k}{m} \frac{|q^{2} |}{d^{2} }\\a=\frac{(9*10^{9} )*(1.6*10^{-19} )^{2} }{(1.6*10^{-27} )*(2.5*10^{-9} )^{2} }\\ a=2.304*10^{16}m/s^{2}  

4 0
3 years ago
Which statement accurately compares the weight of an object on these two planets
wel
"An object weighs about two times as much on Jupiter as on Neptune." Hope this helps :)
5 0
3 years ago
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