INVERSE PROPORTIONALITY ????
1 answer:
Easy peasy
if you had
y is inversely proportioal as x that means
y=k/x wher k is a constant
q is invesely peorportionto the square of t
q=k/(t^2)
t=5, q=9.6
easy peasy
subsiute and find k
9.6=k/(5^2)
9.6=k/25
mutiplyb oths ides by 25
240=k
the equation is
q=240/(t^2)
when t=8 then
q=240/(8^2)
q=240/64
q=3.75
q=2.4 find t
2.4=240/(t^2)
multiply both sides by t^2
2.4t^2=240
divide both sides by 2.4
t^2=100
square root both sides
t=10
a. q=
b. q=3.75
c. t=10
if you had
y is inversely proportioal as x that means
y=k/x wher k is a constant
q is invesely peorportionto the square of t
q=k/(t^2)
t=5, q=9.6
easy peasy
subsiute and find k
9.6=k/(5^2)
9.6=k/25
mutiplyb oths ides by 25
240=k
the equation is
q=240/(t^2)
when t=8 then
q=240/(8^2)
q=240/64
q=3.75
q=2.4 find t
2.4=240/(t^2)
multiply both sides by t^2
2.4t^2=240
divide both sides by 2.4
t^2=100
square root both sides
t=10
a. q=
b. q=3.75
c. t=10
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Answer:
- QN = 3√7
- OI = √7
Step-by-step explanation:
The ratio of corresponding sides DN and KI is 12 : 4 = 3 : 1. The same ratio applies to altitudes DQ and KO. Since the difference between these altitudes is 6 and the difference between their ratio units is 3-1 = 2, each ratio unit must stand for 6/2 = 3 units of linear measure. That is, ...
DQ = (3 units)·3 = 9 units
KO = (3 units)·1 = 3 units
Then the base lengths QN and OI can be found from the Pythagorean theorem:
KI² = KO² +OI²
4² = 3² +OI²
OI = √(16 -9)
OI = √7
QN = 3·OI = 3√7
