Ask question

Ask question

All categories

4 years ago

15

Ashley invests $9,720 in a one-month money market account paying 3.16% simple annual interest and $8,140 in a two-year CD yieldi

ng 3.23% simple annual interest. Assuming Ashley does not reinvest or renew these investments, how much money will she have when both investments reach maturity, to the nearest dollar?

2 answers:

tester [92]4 years ago

5 0

For the first investment. A = P(1 + rt); where p = 9,720, r = 0.0316 and t = 1/12
A = 9720(1 + 0.0316/12) = 9720(1.0026) = $9,746

For the second investment,
A = 8140(1 + 0.0323 x 2) = 8140(1.0646) = $8,666

Total amount she had = $9,746 + $8,666 = $18,412

Elodia [21]4 years ago

3 0

Answer:

D. $18,411

Step-by-step explanation:

I just answered it correct

You might be interested in

The formula for the perimeter of a rectangle is P = 2 (1+w) solve for w.

max2010maxim [7]

$2(1+w)=P\ \ \ \ |\text{use distributive property}\\\\2+2w=P\ \ \ \ |-2\\\\2w=P-2\ \ \ \ |:2\\\\\boxed{w=\dfrac{P-2}{2}}$

5 0

3 years ago

Use a half-angle identity to find the exact value of tan 22.5°.

dusya [7]

Answer:

$\sqrt{2} -1$

Step-by-step explanation:

22.5 degrees is half of 45 degrees (special angle for which we know exactly the value of all three basic trigonometric functions (sine, cosine, and tangent).

So we start recalling the formula for tangent of a half angle: $tan(\frac{\alpha }{2} )= \frac{1-cos(\alpha) }{sin(\alpha) }$

We need just the values of:

$sin(\alpha )=sin(45^o)=\frac{\sqrt{2} }{2}$

and of

$cos(\alpha )=cos(45^o)=\frac{\sqrt{2} }{2}$

to answer the question. Then, we use those values in the original formula for tangent of a half angle:

$tan(\frac{\alpha }{2} )= \frac{1-cos(\alpha) }{sin(\alpha) }\\tan(22.5^o)=\frac{1-\frac{\sqrt{2} }{2} }{\frac{\sqrt{2} }{2}} =\frac{2-\sqrt{2} }{\sqrt{2} } =\frac{2\sqrt{2}-2 }{2} =\sqrt{2} -1$

3 0

4 years ago

Read 2 more answers

Can you please help? The question is in the picture picture. thank you

Naddika [18.5K]

Given:

The value is $\dfrac{\sqrt{2}}{2}$ .

To find:

The values from the given options which are equal to the given value.

Solution:

We have,

$\dfrac{\sqrt{2}}{2}$

It can be written as:

$\dfrac{\sqrt{2}}{2}=\dfrac{1}{\sqrt{2}}$

From the standard trigonometric table, we get

$\sin 30^\circ=\dfrac{1}{2}$

$\sin 45^\circ=\dfrac{1}{\sqrt{2}}$

$\cos 45^\circ=\dfrac{1}{\sqrt{2}}$

$\cos 60^\circ=\dfrac{1}{2}$

$\tan 30^\circ=\dfrac{1}{\sqrt{3}}$

$\tan 45^\circ=1$

From the above values it is clear that the value of $\sin 45^\circ$ and $\cos 45^\circ$ are equal to $\dfrac{1}{\sqrt{2}}$ .

Therefore, $\sin 45^\circ$ and $\cos 45^\circ$ and equal to $\dfrac{\sqrt{2}}{2}$ . So, options B and C are correct.

4 0

3 years ago

1) 1/3<br><br> 2)6<br><br> 3)-6 <br><br> 4)-3<br><br> 5)-1/3<br><br> 6) 3

slega [8]

Answer:

$\frac{3}{1}$ or 3

Step-by-step explanation:

To find the slope find two coordinates and set up the equation $\frac{y_{2}-y_{1} }{x_{2} -x_{1} }$

For the coordinates (0,2) and (2,8) y2 is 8 and y1 is 2. x2 is 2 and x1 is 0. $\frac{8_{}-2_ }{2-0_ }$ you have to do subtraction first. 8-2 = 6 and 2-0 = 2

Now we have the equation $\frac{6}{2}$

this can be simplified to $\frac{3}{1}$

6 0

3 years ago

A ribbon is 4m long. how many pieces each of 30cm long can be cut from the ribbon

labwork [276]

9514 1404 393

Answer:

13

Step-by-step explanation:

4 m is 400 cm, so the number that can be cut is ...

(400 cm)/(30 cm/piece) = 13 1/2 pieces

13 pieces can be cut that are 30 cm long.

6 0

3 years ago

Read 2 more answers