Given 3.72 g of P and 21.28g of Cl, converting these to moles: ( 3.72 g P)(mol P/30.97 g P) = 0.12 mol P (21.28 g Cl)(mol Cl/35.45 g Cl) = 0.60 mol Cl P:Cl = 0.12/0.60, therefore P: Cl =1/5 Therefore, PCl5 hope it helps
Answer:
The concentration of CH₃OH in equilibrium is [CH₃OH] = <em>2,8x10⁻¹ M</em>
Explanation:
For the equilibrium:
CO (g) + 2H₂(g) ⇄ CH₃OH(g) keq= 14,5
Thus:
14,5 =
In equilibrium, as [CO] is 0,15M and [H₂] is 0,36M:
14,5 =
Solving, the concentration of CH₃OH in equilibrium is:
<em>[CH₃OH] = 0,28M ≡ 2,8x10⁻¹ M</em>
I hope it helps!
<span>hydrothermal vents can be one the energy soruces for them</span>
Hydrogine peroxide
Maintains level of hydrogen sulfate inbalance
The maximum percent of yield should be 100%, so It wasn't possible to make a higher than 100% yield like 105% in this problem. If that happens, it will contradict the law of conservation of energy as you can't create mass.
The increased mass might be produced by impurities. One of the examples would be if you rinse the container and left some water. The water is not calculated as a substrate but will increase the results weight.
There also possibilities that some gas in the air react and produce a solid/liquid material. If you don't weight the gas it would seem that the mass increased.