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Anestetic [448]
3 years ago
15

Suppose a lab group reports a percent yield of sand of 105%. Is it really possible to collect more sand than was originally pres

ent? What is a possible explanation for the “extra” product? Do not consider calculation mistakes; think about the procedure used.
Chemistry
1 answer:
just olya [345]3 years ago
4 0
The maximum percent of yield should be 100%, so It wasn't possible to make a higher than 100% yield like 105% in this problem. If that happens, it will contradict the law of conservation of energy as you can't create mass.

The increased mass might be produced by impurities. One of the examples would be if you rinse the container and left some water. The water is not calculated as a substrate but will increase the results weight. 
There also possibilities that some gas in the air react and produce a solid/liquid material. If you don't weight the gas it would seem that the mass increased.
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Which best explains the difference between a ball-and-stick model of a chemical compound and a space-filling model?
Nikolay [14]
Scientists use models to show the characteristics of compounds. Of the different models,ball-and-stick model and space-filling model are commonly used but similar. Ball-and- stick model shows the bond between both atom and not the relative size of the atoms. Space-filling model shows the relative size of the atom and not the bond between the atoms. Both are 3-Dimensional and use color spheres within the model. 
4 0
3 years ago
Read 2 more answers
At 350 k, kc = 0.142 for the reaction 2 brcl(g) ⇀↽ br2(g) + cl2(g) an equilibrium mixture at this temperature contains equal con
djyliett [7]
0.114 mol/l  
The equilibrium equation will be: 
Kc = ([Br2][Cl2])/[BrCl]^2  
The square factor for BrCl is due to the 2 coefficient on that side of the equation.  
Now solve for BrCl, substitute the known values and calculate. 
Kc = ([Br2][Cl2])/[BrCl]^2 
[BrCl]^2 * Kc = ([Br2][Cl2]) 
[BrCl]^2 = ([Br2][Cl2])/Kc 
[BrCl] = sqrt(([Br2][Cl2])/Kc)  
[BrCl] = sqrt(0.043 mol/l * 0.043 mol/l / 0.142) 
[BrCl] = sqrt(0.001849 mol^2/l^2 / 0.142) 
[BrCl] = sqrt(0.013021127 mol^2/l^2) 
[BrCl] = 0.114110152 mol/l  
Rounding to 3 significant figures gives 0.114 mol/l
4 0
3 years ago
How many digits to the right of the decimal point should be used to report the result?
aalyn [17]

Answer:

In engineering and science the common stand is two places.

For example if you get a calculation of 4.567 round up and give the result of 4.57

4 0
3 years ago
Someone Please Help Me out
Kisachek [45]

Answer:

where are u stuck ????

Explanation:

tell us fast

4 0
2 years ago
If an ultraviolet photon has a wavelength of 77.8 nm calculate the energy of one mole ultraviolet photon.
DerKrebs [107]

Answer:

Explanation:

E = (hc)/(λ)

E = (6.624x10^(-27))Js x ((3×10^8)ms^(-1)) /

(77.8x10^(-9)m)

E = 2.55 x 10^(-11) J

7 0
2 years ago
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