Question

Consider the following chemical reaction: CO (g) + 2H2(g) ↔ CH3OH(g) At equilibrium in a particular experiment, the concentrations of CO and H2 were 0.15 M and0.36 M,respectively. What is the equilibrium concentration of CH3OH? The value of Keq for this reaction is 14.5 at the temperature of the experiment. Consider the following chemical reaction: CO (g) + 2H2(g) CH3OH(g) At equilibrium in a particular experiment, the concentrations of CO and H2 were 0.15 M and0.36 M,respectively. What is the equilibrium concentration of CH3OH? The value of Keq for this reaction is 14.5 at the temperature of the experiment. 2.82 ⋅ 10-1 3.72 ⋅ 10-3 1.34 ⋅ 10-3 14.5 7.61 ⋅ 10-3

Answer 1

Answer:

The concentration of CH₃OH in equilibrium is [CH₃OH] = 2,8x10⁻¹ M

Explanation:

For the equilibrium:

CO (g) + 2H₂(g) ⇄ CH₃OH(g) keq= 14,5

Thus:

14,5 = $\frac{[CH_{3}OH]}{[CO][H_{2}]^2}$

In equilibrium, as [CO] is 0,15M and [H₂] is 0,36M:

14,5 = $\frac{[CH_{3}OH]}{[0,15][0,36]^2}$

Solving, the concentration of CH₃OH in equilibrium is:

[CH₃OH] = 0,28M ≡ 2,8x10⁻¹ M

I hope it helps!