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jeka94
3 years ago
8

Consider the following chemical reaction: CO (g) + 2H2(g) ↔ CH3OH(g) At equilibrium in a particular experiment, the concentratio

ns of CO and H2 were 0.15 M and0.36 M,respectively. What is the equilibrium concentration of CH3OH? The value of Keq for this reaction is 14.5 at the temperature of the experiment. Consider the following chemical reaction: CO (g) + 2H2(g) CH3OH(g) At equilibrium in a particular experiment, the concentrations of CO and H2 were 0.15 M and0.36 M,respectively. What is the equilibrium concentration of CH3OH? The value of Keq for this reaction is 14.5 at the temperature of the experiment. 2.82 ⋅ 10-1 3.72 ⋅ 10-3 1.34 ⋅ 10-3 14.5 7.61 ⋅ 10-3
Chemistry
1 answer:
boyakko [2]3 years ago
8 0

Answer:

The concentration of CH₃OH in equilibrium is [CH₃OH] = <em>2,8x10⁻¹ M</em>

Explanation:

For the equilibrium:

CO (g) + 2H₂(g) ⇄ CH₃OH(g) keq= 14,5

Thus:

14,5 = \frac{[CH_{3}OH]}{[CO][H_{2}]^2}

In equilibrium, as [CO] is 0,15M and [H₂] is 0,36M:

14,5 = \frac{[CH_{3}OH]}{[0,15][0,36]^2}

Solving, the concentration of CH₃OH in equilibrium is:

<em>[CH₃OH] = 0,28M ≡ 2,8x10⁻¹ M</em>

I hope it helps!

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8 0
3 years ago
How does the number of subatomic particles change as the carbon isotope<br> decays?
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Answer:

Explanation:

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3 years ago
A solution is made by combining 500 mL of 0.10 M HF (Ka=7.2 x 10^-4) with 300 mL of 0.15 M NaF. What is the pH of the resulting
n200080 [17]

Answer:

b) 3.10

Explanation:

HF ⇄ H + + F

Using Henderson-Hasselbalch Equation:

pH = pKa + log [A-]/[HA].

Where;

pKa = Dissociation constant = -log Ka

Hence, pKa of HF = -log 7.2 x 10^-4 = 3.14266

[A-] = concentration of conjugate base after dissociation = moles of base/total volume

          = 0.15 x 0.3/0.8

               = 0.05625 M

[HA] = concentration of the acid = moles of acid/total volume

             = 0.10 x 0.5/0.8

                    = 0.0625 M

Note: <em>Total volume = 500 + 300 = 800 mL = 0.8 dm3</em>

pH = 3.14266 + log [0.05625/0.0625]

      = 3.14267 + (-0.04575749056)

           = 3.09691250944

<em>From all the available options below:</em>

<em>a) 2.97 </em>

<em>b) 3.10 </em>

<em>c) 3.19 </em>

<em>d) 3.22 </em>

<em>e) 3.32</em>

The correct option is b.

4 0
3 years ago
4
matrenka [14]

Answer:

Yes.

Explanation:

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2 years ago
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