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Neko [114]
3 years ago
15

A solution of cough syrup contains 5.00% active ingredient by volume. If the total volume of the bottle is 44.0 mL , how many mi

lliliters of active ingredient are in the bottle?
Chemistry
1 answer:
Lelechka [254]3 years ago
3 0
2.2 mL is how many mililiters of active ingredient
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The mixture of carbon dioxide and water tastes salt why​
vampirchik [111]

Answer:

When carbon dioxide reacts with water carbonic acid is formed, from which hydrogen ions dissociate increasing the acidity of the systemCarbon dioxide emissions to the atmosphere can therefore increase the acidity of land, sea and air

Explanation:

6 0
3 years ago
If the original solution contained 0.12 mol hcl, what amount of hcl, in moles, will remain when the reaction is complete? 1.4 g
horsena [70]
First, we have to know the reaction between HCl and Zn. This is a single replacement reaction as shown below:

2 HCl + Zn → ZnCl₂ + 2  H⁺

The molar mass for zinc is 65.38 g/mol. Convert mass to moles and compute for moles of HCl needed to completely react.

Mole of Zn = 1.4 g * 1 mol/65.38 g = 0.0214 moles Zn
Moles of HCl reacted =  0.0214 mol Zn * ( 2 mol HCl/1 mol Zn) = 0.0428 mol
Moles HCl remaining = 0.12 - 0.0428 = 0/077 moles HCl
8 0
4 years ago
Read 2 more answers
Why are fungi classified together?
mash [69]

Answer:

A, they get their food in the same way.

Explanation:

Some fungi can be toxic or poisonous.

Example: mushrooms. Mushrooms typically are found in forests and meadows/plains.

Some fungi are glowing, brown, and in many forms/shapes.

In conclusion, fungi all get nutrient from the dirt they grew in, forests can be moist which gives fungi excellent places to form, usually around trees, because they can absorb plenty of nutrients from the dirt.

4 0
3 years ago
(a)Determine the number of KNO3 molecules in 0.750 mol KNO3.
svp [43]

A. The number of molecules in 0.750 mole of KNO₃ is 4.515×10²³ molecules

B. The mass (in milligrams) of 2.39×10²⁰ molecules of Ag₂SO₄ is 124 mg

C. The number of molecules in 3.429 g of NaHCO₂ is 3.04×10²² molecules

<h3>Avogadro's hypothesis </h3>

1 mole of substance = 6.02×10²³ molecules

<h3>A. How to determine the number of molecules </h3>

1 mole of KNO₃ = 6.02×10²³ molecules

Therefore,

0.750 mole of KNO₃ = 0.75 × 6.02×10²³

0.750 mole of KNO₃ = 4.515×10²³ molecules

<h3>B. How to determine the mass of Ag₂SO₄</h3>

6.02×10²³ molecules = 312 g of Ag₂SO₄

Therefore,

2.39×10²⁰ molecules = (2.39×10²⁰ × 312) / 6.02×10²³

2.39×10²⁰ molecules = 0.124 g

Multiply by 1000 to express in mg

2.39×10²⁰ molecules = 0.124 g × 1000

2.39×10²⁰ molecules = 124 mg of Ag₂SO₄

<h3>C. How to determine the number of molecules </h3>

68 g of NaHCO₂ = 6.02×10²³ molecules

Therefore,

3.429 g of NaHCO₂ = (3.429 × 6.02×10²³) / 68

3.429 g of NaHCO₂ = 3.04×10²² molecules

Learn more about Avogadro's number:

brainly.com/question/26141731

5 0
2 years ago
How many grams of CO2 are produced if 2.09 moles of hydrochloric acid are reacted with
Anit [1.1K]

Answer:

The molar mass of CO2 = 44.01 g/mol

Explanation:

Start with 2.09 moles of HCl and convert to moles of CO2 For every 2 moles of HCl used, 1 mole of CO2 is formed.

2.09 mol HCl •(1 mol CO2/2 mol HCl) = 1.045 mol CO2

Now convert moles of CO2 to grams using the molar mass.

1.045 mol CO2 • 44.01 g/mol = 45.99 grams CO2

3 significant figures = 46.0 grams CO2

Hope This Helped

6 0
2 years ago
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