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Virty [35]
2 years ago
14

If 15g of iron reacts with 8.5g of oxygen, how many grams of iron oxide will be produced

Chemistry
1 answer:
just olya [345]2 years ago
6 0

Answer:

23.5g of FeO

Explanation:

Hello,

The question above is asking us to find the mass of iron oxide produced from 15g of Fe and 8.5g of O. Well, to solve this question, we'll require the equation of reaction.

2Fe + O₂ → 2FeO

From the equation of reaction, 2 moles of Fe plus 1 mole of oxygen will produce 2 moles of FeO

Molar mass of Fe = 56g/mol

Molar mass of FeO = 72g/mol

Molar mass of O = 16 × 2 = 32g/mol

Number of moles = mass / molar mass

Mass = number of moles × molar mass

Mass of Fe = 2 × 56 = 112g

Mass of O = 32g

Mass of FeO = 2 × 72 = 144g

From the equation of reaction, (112 + 32)g (Fe + O2) reacts to produce 144g of FeO

114g of reacts produce 114g of FeO

15g of Fe + 8.5g of O2 = ?

(15 + 8.5)g (Fe + O2) = x

X = (23.5 × 114) / 114

x = 23.5g

Therefore, 15g of Fe and 8.5g of O2 will react to produce 23.5g of FeO

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MAXImum [283]

Answer:

2Zn + 2HCI ➡️ ZnCI2 + H2​

LHS of equation

Z = 2

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Cl = 2

RHS of equation

Zn = 1

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as Zn is not equal in number of atoms on both sides of the equation, the equation does not obey the law of conservation of mass

Explanation:

the law of conservation mass states that the mass of an isolated system cannot be created nor destroyed by any chemical reaction or physical transformation. thus, there must be an equal number of atoms of an element present on both sides of the equation.

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2 years ago
"A crosslinked copolymer consists of 57 wt% ethylene (C2H4) repeat units and 43 wt% propylene (C3H6) repeat units. Determine the
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Explanation:

Percentage ethylene by weight = 57%

Percentage propylene by weight = 43%

Suppose in 100 grams of polymer:

Mass of ethylene = 57 g

Mass of propylene = 43 g

Moles of ethylene = \frac{57 g}{28 g/mol}=2.036 mol

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Units of ethylene = 2.036 mol\times N_A

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a) Fraction of ethylene units:

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b ) Fraction of propylene units:

=\frac{1.024mol\times N_A}{2.306 mol\times N_A+1.024 mol\times N_A}=\frac{256}{765}

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Explanation:

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