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3 years ago

If 15g of iron reacts with 8.5g of oxygen, how many grams of iron oxide will be produced

Chemistry

1 answer:

just olya [345]3 years ago

6 0

Answer:

23.5g of FeO

Explanation:

Hello,

The question above is asking us to find the mass of iron oxide produced from 15g of Fe and 8.5g of O. Well, to solve this question, we'll require the equation of reaction.

2Fe + O₂ → 2FeO

From the equation of reaction, 2 moles of Fe plus 1 mole of oxygen will produce 2 moles of FeO

Molar mass of Fe = 56g/mol

Molar mass of FeO = 72g/mol

Molar mass of O = 16 × 2 = 32g/mol

Number of moles = mass / molar mass

Mass = number of moles × molar mass

Mass of Fe = 2 × 56 = 112g

Mass of O = 32g

Mass of FeO = 2 × 72 = 144g

From the equation of reaction, (112 + 32)g (Fe + O2) reacts to produce 144g of FeO

114g of reacts produce 114g of FeO

15g of Fe + 8.5g of O2 = ?

(15 + 8.5)g (Fe + O2) = x

X = (23.5 × 114) / 114

x = 23.5g

Therefore, 15g of Fe and 8.5g of O2 will react to produce 23.5g of FeO

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40.0L of N₂ gas are in a sealed container at STP.How many moles of N₂ are present?9 mol

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Explanation:

We have to find the number of moles of N₂ that are present in a sample that has a volume of 40.0 L at STP.

STP means Standard Conditions of Temperature and Pressure. These conditions are 273.15 K and 1 atm. We know that 1 mol of N₂ will occupy 22.4 L. We can use that ratio to find the answer to our problem.

1 mol of N₂ = 22.4 L

moles of N₂ = 40.0 L * 1 mol/(22.4 L)

moles of N₂ = 1.79 mol

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Which of the following shows the conservation of mass during cellular respiration? 3 CO2 3 H2O energy → 3 C6H12O6 3 O2 6 CO2 6 H

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The reaction that has been, following the law of conservation of mass has been $\rm C_6H_1_2O_6\;+\;6\;O_2\;\rightarrow\;6\;CO_2\;+\;6\;H_2O\;+\;Energy$ .

The law of conservation has been given in the chemical reaction that there has been no loss or gain of the mass and energy.

The law of conservation has been evident when there has been an equal number of atoms of each element on the product and the reactant side.

<h3 /><h3>Conservation of mass in Cellular respiration</h3>

The following reactions have been identified as:

$\rm 3\;CO_2\;+\;3\;H_2O\;+\;Energy\;\rightarrow\;3\;C_6H_1_2O_6$

Carbon atoms

Reactant = 3

Product = 18

Oxygen atoms

Reactant = 9

Product = 18

Hydrogen atoms

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The number of atoms is not equal on the product and reactant side, thus not follows the law of conservation of mass.

$\rm 3\;O_2\;+\;6\;CO_2\;+\;6\;H_2O\;+\;Energy\;\rightarrow\;C_6H_1_2O_6\;+\;6\;O_2$

Carbon atoms

Reactant = 6

Product = 6

Oxygen atoms

Reactant = 24

Product = 18

Hydrogen atoms

Reactant = 12

Product = 12

The number of atoms is not equal on the product and reactant side, thus not follows the law of conservation of mass.

$\rm C_6H_1_2O_6\;+\;6\;O_2\;\rightarrow\;6\;CO_2\;+\;6\;H_2O\;+\;Energy$

Carbon atoms

Reactant = 6

Product = 6

Oxygen atoms

Reactant = 18

Product = 18

Hydrogen atoms

Reactant = 12

Product = 12

The number of atoms is equal on the product and reactant side, thus follows the law of conservation of mass.

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Carbon atoms

Reactant = 6

Product = 0

Oxygen atoms

Reactant = 12

Product = 12

Hydrogen atoms

Reactant = 24

Product = 0

The number of atoms is not equal on the product and reactant side, thus not follows the law of conservation of mass.

Thus, the reaction that has been following the law of conservation of mass has been $\rm C_6H_1_2O_6\;+\;6\;O_2\;\rightarrow\;6\;CO_2\;+\;6\;H_2O\;+\;Energy$ .

Learn more about law of conservation, here:

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