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3 years ago

What is the mass in grams of 2.50 mol of ammonia vapor, NH3?

Chemistry

1 answer:

Crank3 years ago

7 0

Molar mass:-

$\\ \tt\longmapsto 14+3(1)=17g/mol$

Now

$\\ \tt\longmapsto Given\:mass=No\;of\:moles\times Molar\;mass$

$\\ \tt\longmapsto Given\:mass=17(2.5)$

$\\ \tt\longmapsto Given\:mass=42.5g$

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How would a system in which both matter and energy are exchanged freely between the system and the surroundings be classified? (

Nata [24]

Answer:

An open system

Explanation:

An open system is a system in which both matter and energy are exchanged freely between the system and the surroundings.

An example is a pot of water boiling on the stove. The surroundings (the stove) can supply heat energy to the water and the water can escape into the atmosphere.

A closed system is a system in which energy but not matter is exchanged freely between the system and the surroundings.

An example is a pressure cooker on the stove. The surroundings (the stove) can supply heat energy to the food inside, but no matter can escape through the closed lid.

An isolated system is a system in which neither energy nor matter can be exchanged between the system and the surroundings.

An example is a thermos of hot soup. The cap prevents matter from escaping and the shiny interior reflects heat back into the soup.

8 0

3 years ago

A piece of wood has a labeled length value of 63.2 cm. You measure its length three times and record the following data: 63.1 cm

Ulleksa [173]

Percent error (%)= $\frac{\left | Accepted value - Measured value \right |}{Accepted value}\times 100$

Accepted value is true value.

Measured values is calculated value.

In the question given Accepted value (true value) = 63.2 cm

Given Measured(calculated values) = 63.1 cm , 63.0 cm , 63.7 cm

1) Percent error (%) for first measurement.

Accepted value (true value) = 63.2 cm, Measured(calculated values) = 63.1 cm

Percent error (%)= $\frac{\left | Accepted value - Measured value \right |}{Accepted value}\times 100$

$Percent error = \frac{\left | 63.2 - 63.1 \right |}{63.2}\times 100$

$Percent error = \frac{0.1}{63.2}\times 100$

$Percent error = 0.00158\times 100$

Percent error = 0.158 %

2) Percent error (%) for second measurement.

Accepted value (true value) = 63.2 cm, Measured(calculated values) = 63.0 cm

Percent error (%)= $\frac{\left | Accepted value - Measured value \right |}{Accepted value}\times 100$

$Percent error = \frac{\left | 63.2 - 63.0 \right |}{63.2}\times 100$

$Percent error = \frac{0.2}{63.2}\times 100$

$Percent error = 0.00316\times 100$

Percent error = 0.316 %

3) Percent error (%) for third measurement.

Accepted value (true value) = 63.2 cm, Measured(calculated values) = 63.7 cm

Percent error (%)= $\frac{\left | Accepted value - Measured value \right |}{Accepted value}\times 100$

$Percent error = \frac{\left | 63.2 - 63.7 \right |}{63.2}\times 100$

$Percent error = \frac{\left | -0.5 \right |}{63.2}\times 100$

$Percent error = \frac{(0.5)}{63.2}\times 100$

$Percent error = 0.00791\times 100$

Percent error = 0.791 %

Percent error for each measurement is :

63.1 cm = 0.158%

63.0 cm = 0.316%

63.7 cm = 0.791%

7 0

3 years ago

Suppose that a dependent quantity increases when the independent quantity is decreased. This kind of proportional relationship b

Anna71 [15]

I thinks it’s not this article we should cajnges it

3 0

3 years ago

PLEASE PLEASE PLEASE HELP ME

Neko [114]

In descending order from top:

E
F
D
A
C
B

All you really need to do is remember the symbols of each, and you’ve got it.

8 0

3 years ago

Read 2 more answers

suppose you are testing the buoyancy of different objects . study the table and choose object with the greatest buoyant force

Alika [10]

The formula to calculate buoyant force (FB) states that the upward force exerted on an immersed object is equal to the density (ρ ) of the fluid multiplied by both the fluid’s displaced volume (V) and the gravitational acceleration (g), or
FB = ρ x V x g.
I hope that helped with what you're doing.
You can also try water displacement in a graduated cylinder.

7 0

3 years ago