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3 years ago

What is the mass in grams of 2.50 mol of ammonia vapor, NH3?

Chemistry

1 answer:

Crank3 years ago

7 0

Molar mass:-

$\\ \tt\longmapsto 14+3(1)=17g/mol$

Now

$\\ \tt\longmapsto Given\:mass=No\;of\:moles\times Molar\;mass$

$\\ \tt\longmapsto Given\:mass=17(2.5)$

$\\ \tt\longmapsto Given\:mass=42.5g$

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Calculate the ph of a buffer that is 0.145 m hc2h3o2 and 0.202 m kc2h3o2. The ka for hc2h3o2 is 1.8 × 10-5.

koban [17]

Answer:

pH = 4.8

Explanation:

A buffer is formed by a weak acid (0.145 M HC₂H₃O₂) and its conjugate base (0.202 M C₂H₃O₂⁻ coming from 0.202 M KC₂H₃O₂). The pH of a buffer system can be calculated using Henderson-Hasselbalch's equation.

$pH = pKa + log\frac{[base]}{[acid]} \\pH = -log(1.8 \times 10^{-5} )+log(\frac{0.202M}{0.145M} )\\pH=4.8$

6 0

3 years ago

How does the number of reactants in a double-displacement reaction

mojhsa [17]

In a typical double displacement reaction, you would have a total of two products (AB + CD —> AD + BC).

5 0

2 years ago

Help plz:)))I’ll mark u Brainliest

Triss [41]

Answer:

Explanation:

We want the energy required for the transition:

CO 2 ( s ) + Δ → C O 2 ( g )

Explanation:

We assume that the temperature of the gas and the solid are EQUAL.

And thus we simply have to work out the product:

2 × 10^ 3 ⋅ g × 196.3 ⋅ J ⋅ g − 1 to get an answer in Joules as required.

What would be the energy change for the reverse transition:

C O 2 ( g ) + → C O 2 ( s ) ?

6 0

3 years ago

In a 51.0-g aqueous solution of methanol ch4o the mole fraction of methanol is 0.270. what is the mass of each component?

gladu [14]

Mole fraction is another way of expressing the concentration of a solution or mixture. It is equal to the moles of one component divided by the total moles.

mass CH4O = 0.270 (51) = 13.77 g methanol

water = 51 - 13.77 = 37.23 g water

Hope this answers the question. Have a nice day.

4 0

4 years ago

LICUICY NICULUM

Evgen [1.6K]

Answer:

Missing component

Cl₂

H₂O

Explanation:

Reaction given:

? + 2NaBr → 2NaCl+Br

Mg+? → MgO+H2

missing component = ?

Solution:

Reaction 1

? + 2NaBr -----→ 2NaCl + Br

if we look at the reactants and products there is one element is in product side but not shown in the reactant side.

In products there are following atoms

Na (Sodium)

Cl (Chlorine)

Br (Bromine)

In Reactant there are following atoms

Na (Sodium)

Br (Bromine)

So only Chlorine is missing in the reactant side.

if we put chlorine in the reactant then this reaction will be complete

Cl + 2 NaBr -----→ 2NaCl + Br

So chlorine react with water and give sodium chloride and bromine molecule, this is a single displacement reaction and chlorine replace bromine in the above reaction

Now balance the equation

Cl₂ + 2 NaBr -----→ 2NaCl + Br₂

So, the missing component is

Cl₂

____________

Reaction 2

Mg + ? ---------→ MgO + H₂

if we look at the reactants and products there are two element in product side but not shown in the reactant side.

In products there are following atoms

Mg (Magnesium)

O (Oxygen)

H (Hydrogen)

In Reactant there is only one following atom

Mg (Magnesium)

So Oxygen and Hydrogen is missing in the reactant side.

if we put water molecule (H₂O) in the reactant then this reaction will be complete

Mg + H₂O ---------→ MgO + H₂

in this reaction magnesium (Mg) react with water (H₂O) and give magnesium oxide and hydrogen gas.

So, the missing component is

H₂O

3 0

3 years ago

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