Answer:
Mass fraction = 0.08004
Mole fraction = 0.0377
Explanation:
Given, Mass of NaOH = 8.70 g
Mass of solution = 8.70 + 100 g = 108.70 g
= 0.08004
Molar mass of NaOH = 39.997 g/mol
The formula for the calculation of moles is shown below:
Thus,

Given, Mass of water = 100 g
Molar mass of water = 18.0153 g/mol
The formula for the calculation of moles is shown below:
Thus,

So, according to definition of mole fraction:
Answer:
235 miles equals 5,280 feet
Explanation:
<h3>
Answer:</h3>
LiOH(aq) +HCl(aq)→ LiCl(aq) + H₂O(l)
Salt formed is LiCl
<h3>
Explanation:</h3>
- Arrhenius acid refers to a substance that ionizes in water to generate protons or hydrogen ions.
- Examples of Arrhenius acid include acids such as HCl, H₂SO₄ and HNO₃.
- A reaction between Lithium hydroxide and an Arrhenius acid such as HCl will yield a salt and water.
That is;
LiOH(aq) +HCl(aq)→ LiCl(aq) + H₂O(l)
- The salt formed is LiCl
- The reaction is an example of neutralization reaction.
The major drawback of fossil fuels is that they warm the planet i.e. they cause global warming.
The reaction typically gives off heat and light as well. The general equation for a complete combustion reaction is:
Fuel + O2 → CO2 + H2O + ENERGY
<h3>
Disadvantages of Fossil fuels</h3>
The term "fossil fuels" refers to flammable organic geologic formations, including dead organic matter that has been buried hundreds of feet beneath sediment.
- Fossil fuel emissions include various oxides, such as carbon, nitrogen, and sulfate, which cause acid rain and harm the soil's fertility and water quality.
- Both coal and petroleum burning discharge a significant amount of pollutants into the atmosphere, contributing to pollution levels.
- Gases like carbon dioxide are released through the burning of fossil fuels, which aids in climate change.
To view similar questions on Fossil fuels, refer to:
brainly.com/question/14339391
#SPJ4
Write an balance the equation
Na2O + H2O -> 2 NaOH
Calculate the molecular mass of Na2O and NaOH from the atomic mass from the periodic table.
Na = 23
O=16
H=1
Na2O = 23 * 2 + 16 = 62
NaOH = 23+16+1= 40
For the stoichiometry of the reaction one mole of Na2O = 62g produce two mol of NaOH = 2* 40= 80 g
120 g Na2O x 80g NaOH / 62g Na2O=
154.8 g NaOH