Explanation:
I can give you some examples;
1) water
2) biomass
3)Soil
4) forest...
I hope this will help you
The heat used in phase changes is calculated by multiplying the mass of the substance by the energy of the phase change. In this case, for liquid to boil, we would find total heat by multiply the mass of liquid by the latent heat of vaporization (Hvap). If we are instead given the Hvap and the total heat of 1 kJ, we would divide 1 kJ by the Hvap (which is usually in kJ/kg) to get the mass of liquid boiled (in kg).
From the given observations,
You can see that as the concentration is doubled, half-life is halved.
That is,half-life is inversely proportional to concentration
As t( half-life) ~ 1/a^(n-1)
For this case n = 2,second order reaction.
R = k X a^n
Using the above formula you will get the rate and rate constant.
Answer:
His conclusion is wrong
Explanation:
Now we must know that there are various rate laws.
In a zero order rate law, the rate of reaction is independent of the initial concentration of reactants. Hence varying the initial concentration of the reactants results in no change of the rate of reaction.
In first and second order rate laws, the rate of reaction varies with the concentration of one or two reactants in either case respectively.
Having said these, the student does not need to change the temperature but rather designate the reaction as zero order. The rate of reaction is independent of the initial concentration of reactants.