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forsale [732]
3 years ago
5

Consider an electrochemical cell based on the reaction: 2H+ (aq) + Sn (s) → Sn2+ (aq) + H2 (g) Which of the following actions wo

uld not change the measured cell potential? Consider an electrochemical cell based on the reaction: 2H+ (aq) + Sn (s) Sn2+ (aq) + H2 (g) Which of the following actions would not change the measured cell potential? addition of more tin metal to the anode compartment increasing the pressure of hydrogen gas in the cathode compartment lowering the pH in the cathode compartment increasing the tin (II) ion concentration in the anode compartment Any of the above will change the measured cell potential. Request Answer
Chemistry
1 answer:
Ilya [14]3 years ago
7 0

Answer:

The only thing that will not affect the potential is the adition of solid Sn.

Explanation:

The potencial of a cell is linked to the concentration of the substances involved in the reactions by the equation of Nernst. So a change of one of them would change the cell potential.

E=E^{\circ}-\frac{R*T}{n*F}*ln(Keq)

The Keq for this reaction is:

K_{eq}=\frac{[Sn^{2+}]*[H_2]}{[H^+]}

<em>Sn is not included because it's in solid state. </em>

As can be seen, changing the concentrations of H2 (increasing the pressure), H+ (lowering the pH) or Sn2+ will affect the potential.

The only thing that will not affect it is the adition of solid Sn.

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This energy level can have values of orbital angular momentum l = 0, 1, 2, 3

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Therefore,

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<span>ml = 0 </span>

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l = 3

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Now adding up all the number of ml’s will give us the total number of orbitals:

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Alternatively, we can simply use the formula:

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8 0
3 years ago
How many millimeters are there in 5.12 x 10^5
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Silver nitrate, AgNO3 reacts with sodium
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