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crimeas [40]
3 years ago
5

What is the number of moles of Sodium Chloride (NaCl) that is present in 29.22g sample of it?

Chemistry
2 answers:
kodGreya [7K]3 years ago
5 0

Answer:

\boxed {\boxed {\sf 0.5000 \ mol \ NaCl}}

Explanation:

We are asked to convert grams to moles. We must use the molar mass or the grams in 1 mole of a substance. These values are found on the Periodic Table as the atomic mass, but the units are grams per mole (g/mol) instead of atomic mass units (amu).

We are given the compound sodium chloride or NaCl. Look up the molar masses of the individual elements.

  • Na:  22.9897693 g/mol
  • Cl: 35.45 g/mol

The formula for the compound does not contain any subscripts, so there is 1 mole of each element in 1 mole of the compound. Add the molar masses together to find sodium chloride's molar mass.

  • NaCl: 22.9897693 + 35.45= 58.4397693 g/mol

Now we can use the molar mass to create a ratio. We know there are 58.4397693 grams of NaCl in 1 mole of NaCl.

\frac {58.4397693  \ g \ NaCl}{ 1 \ mol \ NaCl}

Multiply by the number of grams provided in the problem: 29.22

29.22 \ g\ NaCl*\frac {58.4397693  \ g \ NaCl}{ 1 \ mol \ NaCl}

Flip the ratio so the units of grams of NaCl cancel.

29.22 \ g\ NaCl*\frac { 1 \ mol \ NaCl}{58.4397693  \ g \ NaCl}

29.22*\frac { 1 \ mol \ NaCl}{58.4397693}

\frac {29.22}{58.4397693}  \ mol \ NaCl

0.5000019738 \ mol \ NaCl

The original measurement of grams has 4 significant figures, so our answer must have the same. For our answer, that is the ten-thousandth place. The 0 to the right of this place (0.5000019738) tells us to leave the 0 in the ten-thousandth place.

0.5000 \ mol \ NaCl

There are approximately <u>0.5000 moles of sodium chloride in a 29.22 gram sample of sodium chloride.</u>

Liula [17]3 years ago
3 0
There are 0.5 moles of NaCl present in a 29.22g sample.

to find moles of a compound you would look at the periodic table to find the mass. in this case, the mass of NaCl is 58.44 g/mol. now, you divide the sample mass of 29.22g by 58.44 g/mol. the grams will cancel each other out and you’re left with 0.5 mol in that sample

hope this helps!
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