Answer:
The percent abundance of oxygen-18 is 1.9066%.
Explanation:
The average atomic mass of oxygen is given by:
Where:
m: is the atomic mass
%: is the percent abundance
Since the sum of the percent abundance of oxygen isotopes must be equal to 1, we have:
Hence, the percent abundance of O-18 is:
Hence, the percent abundance of oxygen-18 is:
Therefore, the percent abundance of oxygen-18 is 1.9066%.
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Answer:
15.5 km
Explanation:
1.55x10^4m
1.55x10000m
15500m
1km=1000m
b=15500m
1km*15500m=b*1000m
1km*15500m/1000m=b*1000m/1000m
b=15.5km
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Solution:
That is depend on the amount of sugar in the original (14.630) bar.
For example, if the 14.630g bar contains 1.234g of sugar (=1234mg),
Then by proportion the 5.000g bar contains:
1234 x (5.000/14.630) = 341.76 mg sugar.