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ANTONII [103]
2 years ago
9

Which substance is not a structural isomer of hexyne?

Chemistry
1 answer:
stich3 [128]2 years ago
5 0

Answer:

c) 3,3-dimethylpent-1-yne

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Give the formula of the chlorine ion​
seraphim [82]

Answer:

fluorine plus chlorides think

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3 years ago
Convert 3.00 moles As2S3 to grams.
givi [52]

738.1146 grams, your're welcome

7 0
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Which of the following substances has the highest melting point?
Aleksandr [31]

Nonane (b) has the highest melting point.

-----------------------------

A caveat: I'm assuming that we're dealing with the straight-chain isomers of these alkanes (specifically pentane and nonane). The straight-chain isomer of pentane (<em>n</em>-pentane, CH3-[CH2]3-CH3) has a melting point of -129.8 °C; the straight-chain isomer of nonane (<em>n-</em>nonane, CH3-[CH2]7-CH3) has a melting point of -53.5 °C. The pattern holds as you go down (or up): The more carbon atoms, the higher the melting point. So, in decreasing order of melting points here, you'd have the following: nonane > pentane > butane > ethane.

However, one structural isomer of pentane, neopentane, has a melting point of -16.4 °C, which is <em>higher </em>that the melting point of <em>n</em>-nonane despite neopentane having the same molecular formula as its straight-chain isomer. Of course, you're not to blame for coming up with this question; this is just some extra info to keep in mind.

5 0
2 years ago
Help! This is due tomorrow and my teacher didn't explain this topic very well so I'm totally lost!
nydimaria [60]

Answer:

sorry I'm a dumb small brain

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my genes

6 0
2 years ago
Two trials are run, using excess water. In the first trial, 7.8 g of Na2O2(s) (molar mass 78 g/mol) is mixed with 3.2 g of S(s).
Tema [17]

Answer:

The answer is "Option C".

Explanation:

Given equation:

2Na_20_2 (s)+S(s)+2H_2O \longrightarrow  4NaOH(aq)+SO_2(aq)

\to \Delta H^{\circ}_{rxn} (298\ K) = -610 \frac{kJ}{mol}

\to Na_2O_2  \ Mass = 7.8 \ g\\\\ \to  Na_2O_2 \ Molar \ mass = 78 \frac{g}{mol}

Na_2O_2 Has been the reactant which is limited since the two experiments are equal toNa_2O_2 for relationship between stress amounts.

Na_2O_2, n =\frac{Mass of Na_2O_2}{Molar mass of Na_2 O_2}=\frac{7.8 \ g}{78 \frac{g}{mol}} =0.1 \ mol \\\\q=\Delta H^{\circ}_{rxn} \times n = \frac{ -610 \ kJ}{ 2 \ mol \ Na_2 O_2} \times 0.1 \ mol  \ Na_2O_2= 30.5 \ KJ\\\\

Limiting reactant =Na_2O_2

q=30.5 \ kJ \approx 30 \ kJ

8 0
3 years ago
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