Balance Chemical Equation,
2 CO + O₂ → 2CO₂
Acc. to this reaction,
88 g (2 mole) of CO₂ was produced when = 56 g (2 mole)of CO was reacted
So,
24.7 g of CO₂ will be produced by reacting = X g of CO
Solving for X,
X = (56 g × 24.7 g) ÷ 88 g
X = 2.26 g ÷ 88 g
X = 0.0257 g of CO
Result:
0.0257 g of CO is required to be reacted with excess of O₂ to produce 24.7 g of CO₂.
Answer : The correct option is B- Towards the left.
Solution : Given,
Force on car in upward direction, 
= 6000 N
Force on car in downward direction, 
= 6000 N
Force on car in right direction, 
= 5000 N
Force on car in left direction, 
= 6000 N
Force : Force is equal to the mass multiplied by the acceleration. The force is directly proportional to the acceleration.
Formula : F = m × a
where, F is force, m is mass and a is acceleration.
From the given diagram we conclude that the and are in opposite direction and the force acting on car are same. So, their net force is zero.
And in case of and , the net force will not be zero because force acting on car are different. The car will accelerate towards left direction because is higher than the .
So, the car will accelerate towards left direction.
Answer:
If 1,079.75 Joules of heat are added to 77.75 grams of water, by 3.32 degrees Celsius the temperature of water will increase
Explanation:
Here , q = heat added / removed from the substance
m = mass of the substance taken
= Change in temperature
C = specific heat capacity of the substance
In liquid state the value of C for water is :
Given values :
q = 1079.75 J
m = 77.75 gram
Insert the value of C, m , q in the given equation
on transposing ,
Answer:
a) 7.0.
b) Nickel sulfate hepta hydrate.
c) 280.83 g/mol.
d) 44.9%.
Explanation:
<u><em>a) What is the formula of the hydrate?</em></u>
The mass of the hydrated sample (NiSO₄.xH₂O) = 5.0 g,
The mass of the anhydrous salt (NiSO₄) = 2.755 g,
The mass of water = 5.0 g - 2.755 g = 2.245 g.
∴ no. of moles of water = mass/molar mass = (2.245 g)/(18.0 g/mol) = 0.1247 mol.
∴ no. of moles of anhydrous salt (NiSO₄) = mass/molar mass = (2.755 g)/(154.75 g/mol) = 0.0178 mol.
∴ water of crystallization in the sample (x) = no. of moles of water/no. of moles of anhydrous salt (NiSO₄) = (0.1247 mol)/(0.0178 mol) = 7.0.
<u><em>b) What is the full chemical name for the hydrate?</em></u>
The name of the salt (NiSO₄.7H₂O) is Nickel sulfate hepta hydrate.
<u><em>c) What is the molar mass of the hydrate? </em></u>
(NiSO₄.7H₂O)
The molar mass = molar mass of NiSO₄ + 7(molar mass of H₂O) = (154.75 g/mol) + 7(18.0 g/mol) = 280.83 g/mol.
<em><u>d) What is the mass % of water in the hydrate?</u></em>
The mass % of water = (mass of water)/(mass of hydrated sample) x 100 = (2.245 g)/(5.0 g) x 100 = 44.9%.
