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Marina CMI [18]
3 years ago
13

How many orbitals are there in the n = 4 level of the h-atom?

Chemistry
1 answer:
Nikolay [14]3 years ago
8 0

The H-atom has fourth energy level with n=4.

This energy level can have values of orbital angular momentum l = 0, 1, 2, 3

Now each l can also have magnetic momentum ml from – l to l.

Therefore,

l = 0

<span>ml = 0 </span>

l = 1

ml = -1, 0, 1

l = 2

ml = -2, -1, 0, 1, 2

l = 3

ml = -3, -2, -1, 0, 1, 2, 3

Now adding up all the number of ml’s will give us the total number of orbitals:

orbitals = 1 + 3 + 5 + 7

orbitals = 16

 

Alternatively, we can simply use the formula:

<span>orbitals = n^2 = 4^2 = 16</span>

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Calculate the percent ionization of nitrous acid in a solution that is 0.249 M in nitrous acid. The acid dissociation constant o
sattari [20]

Answer:

4.26 %

Explanation:

There is some info missing. I think this is the original question.

<em>Calculate the percent ionization of nitrous acid in a solution that is 0.249 M in nitrous acid. The acid dissociation constant of nitrous acid is  4.50  ×  10 ⁻⁴.</em>

<em />

Step 1: Given data

Initial concentration of the acid (Ca): 0.249 M

Acid dissociation constant (Ka): 4.50  ×  10 ⁻⁴

Step 2: Write the ionization reaction for nitrous acid

HNO₂(aq) ⇒ H⁺(aq) + NO₂⁻(aq)

Step 3: Calculate the concentration of nitrite in the equilibrium ([A⁻])

We will use the following expression.

[A^{-} ] = \sqrt{Ca \times Ka } = \sqrt{0.249 \times 4.50 \times 10^{-4}  } = 0.0106 M

Step 4: Calculate the percent ionization of nitrous acid

We will use the following expression.

\alpha = \frac{[A^{-} ]}{[HA]} \times 100\% = \frac{0.0106M}{0.249} \times 100\% = 4.26\%

4 0
3 years ago
Help pleaseeeeeeeeeee
hichkok12 [17]

Answer:

D 1 and 3 only I am not sure

Explanation:

6 0
3 years ago
What is the most important monosaccharide on Earth?
Nikolay [14]
Probably the most important monosaccharide on earth is Glucose. it is used in many bodily functions and it a key source of energy

5 0
3 years ago
Select the answers below that represent the ionic compounds in this list: na2so4 h2so4 ch3-ch3 n2o4 cacl2 ca3(po4)2
yarga [219]

Ionic compounds are those compounds which form an ion or dissociates into ions when placed in a solution. These compounds are made up of a metal and non metal. From the choices, here are the ionic compounds:

na2so4

h2so4

cacl2

<span>ca3(po4)2</span>

3 0
3 years ago
What is the concentration of H+ ions at a pH = 11?
natta225 [31]

Answer:

\huge 1 × {10}^{-11} \: \: M

Explanation:

The pH of a solution can be found by using the formula

pH = - log [ {H}^{+} ]

Since we are finding the H+ ions we find the antilog of the pH

So we have

11 =  -  log({H}^{+})  \\ {H}^{+} =  {10}^{ - 11}

We have the final answer as

1 × {10}^{-11} \: \: M

Hope this helps you

6 0
3 years ago
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