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Yuliya22 [10]
3 years ago
9

Write a balanced chemical equation between magnesium chloride and sodium phosphate. Determine the grams of magnesium chloride th

at are needed to produce 1.33 x 10^{23} formula units of magnesium phosphate.
Chemistry
1 answer:
zlopas [31]3 years ago
5 0

Answer:

The grams of MgCl₂ that are needed are 63.1 g

Explanation:

First of all, try to think the equation and ballance it. This is it:

3MgCl₂  +  2Na₃PO₄  →  Mg₃(PO₄)₂  +  6NaCl

Let's convert our f.u in mol

1 mol =  6.02x10²³ formula units (Avogadro's number)

So f.u / Avogadro = mol

1.33x10²³ / 6.02x10²³ = 0.221 moles.

So 1 mol of phosphate sodium comes from 3 mol of magnesium chloride.

How many mol of magnesium chloride are necessary, for 0.221 mol of phosphate.?

0.221 moles .3 = 0.663 moles.

Molar mass of MgCl₂ is 95.2 g/m

0.663 moles . 95.2 g/m = 63.1 g

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Explanation:

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Therefore, molecules of S present in 33.76 moles are calculated as follows.

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