PV=nRT
P = 85.0 x 10^3 Pa
T = 273 + 20 = 293 K
n = 2.0 moles
R = 8.314 m3. pa / mol .K
V = 2.0 x 293 x 8.314 / 85.0x10^3 = 0.195623529 m^3
Answer:
B) 3rd
Explanation:
The 3rd ionization energy represents the removal of electrons from a filled core shell.
The electron configuration of calcium is [Ar]4s^2. Hence after the removal of the second electron from the 4s^2 orbital, a lot of energy is required to remove an electron from the next completely filled core shell. This is the highest successive jump in ionization energy. The other options in the question deal with electrons found on the same shell.
Answer:
A car traveling 25 KM/H
Explanation:
It has the largest mass and speed.
The equation that we will use to solve these two questions is:
c = lambda * f where:
c is the speed f the wave
lambda is the wavelength of the wave
f is the frequency of the wave
Question 1:
we want to find f
c is assumed to be the speed of light = 3*10^8 m/sec
lambda = 5.6 * 10^10 cm = 560 * 10^6 meters
Substitute in the equation to get f as follows:
3*10^8 = 560*10^6*f
f = (3*10^8) / (560*10^6) = 0.5357 Hz
Question 2:
we want to find lambda
c is assumed to be the speed of light = 3*10^8 m/sec
f is given as 0.1096 Hz
Substitute in the equation to get lambda as follows:
3*10^8 = lambda * 0.1096
lambda = (3*10^8) / (0.1096) = 2.737226*10^9 meters
