Atoms with a low electronegativity,like lithium,have a weak attractive force for electrons because

Disadvantages of charcoal

ziro4ka [17]

Answer: It is not renewable

Charcoal contains high amount of CO2 emission.

Charcoal when burned emits radiation and even clean coals produces methane.

Explanation:

6 0

3 years ago

Calculate the molarity of 0.50 mol MgCl2 in 750 ml of solution.

Vedmedyk [2.9K]

Answer : The correct answer for molarity of MgCl₂ solution is 0.67 M.

Molarity :

It expresses concentration of any solution . It can be defined as mole of solute present in volume of solution in Liter .

It uses unit M or $\frac{mol}{L}$

It can be formulated as :

$Molarity (\frac{mol}{L} ) = \frac{mole of solute (mol)}{volume of solution (L)}$

Given : mol of MgCl₂ (solute ) = 0.50 mol

Volume of solution = 750 mL

Following steps can be done :

Step 1 ) To convert volume of solution from mL to L

1 L = 1000 mL

$Volume of solution = 750 mL * \frac{1 L}{1000mL}$

Volume of solution = 0.750 L

Step 2) To find molarity

Plugging mole of solute and volume of solution in molarity formula as :

$Molarity = \frac{0.50 mol}{0.750 L }$

$Molarity = 0.67 \frac{mol}{L}$

Hence molarity of MgCl₂ solution is 0.67 M

4 0

4 years ago

Read 2 more answers

Watch the animation and observe the titration process of a standard 0.100 M sodium hydroxide solution with 50.0 \rm ml of a 0.10

yuradex [85]

Answer:

Answers are in the explanation

Explanation:

a. The statments are:

The titration process is based on a chemical reaction. TRUE. A titration is the chemical reaction between an acid and a base.

The pH of the solution at the equivalence point is 7. TRUE. In a titration of strong acid with strong base the equivalence point is 7

At the endpoint, the pH of solution is 10 and the color of solution is pink. FALSE. The endpoint in a strong acid - strong base titrationmust be near to equivalence point at pH = 7.

At the beginning of the titration process, the pH of the solution increases rapidly. FALSE. At beginning of a titration, the pH of the solution increases slowly.

The chemical reaction involved in an acid-base titration is a neutralization reaction. TRUE. In the reaction, you are neutralizing an acid (HCl) with a base (NaOH)

Before any base is added to the solution, the pH of the solution is high. FALSE. The addition of a base increases pH that is, in the beginning, low.

In a titration process, the endpoint is reached before the equivalence point. FALSE. In a titration process, the endpoint is reached in the equivalence point

The pH of the solution changes very slowly at the equivalence point. FALSE. At the equivalence point, the pH changes rapidly.

b. For the reaction

NaOH + HCl → H₂O + NaCl

As the reaction is 1:1 and molarity of both solutions are the same, additions < 100mL of NaOH will stay before the equivalence point, equivalence point will be in 100mL and additions > 100mL of NaOH will stay after the equivalence point.

The conditions are:

10.0mL of 1.00 M NaOH before the equivalence point

150 mL of 1.00 M NaOH after the equivalence point

5.00 mL of 1.00 M NaOH before the equivalence point

50.0 mL of 1.00 M NaOH before the equivalence point

200 mL of 1.00 M NaOH after the equivalence point

I hope it helps!

7 0

3 years ago

Read 2 more answers

Physics vs organic chemistry which is harder

guajiro [1.7K]

Organic chemistry was definitely harder for me, though this is a matter of opinion and learning style. If you are good with logic, then organic chemistry might not be so hard, or at least that's what my professor said. A lot of physics was just knowing how to use formulas and then plugging and chugging, and knowing basic outcomes of physical reactions. It's a whole other story if you take calculus based physics.
Good luck.

3 0

4 years ago

g 250. mL of a solution is created and has a molarity of 1.50 M. What is the molality of this solution if the volume and density

nika2105 [10]

Answer:

1.30 m

Explanation:

First we calculate the number of moles of solute in the solution, using the definition of molarity:

Molarity = moles / liters

Converting 250 mL ⇒ 250 / 1000 = 0.250 L

moles = 1.50 M * 0.250 L = 0.375 moles

Then we calculate the mass of solvent, using the given volume and density:

1.15 g/mL * 250 mL = 287.5 g

Converting 287.5 g to kg ⇒ 287.5 / 1000 = 0.2875 kg

Now we calculate the molality of the solution:

molality = moles of solute / kg of solvent = 0.375 mol / 0.2875 kg

molality = 1.30 m

8 0

3 years ago