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iragen [17]
3 years ago
6

Which of the following are advantages of the SI system?

Chemistry
2 answers:
Leya [2.2K]3 years ago
7 0

A      b                                              c                     ar e the correect ones

lions [1.4K]3 years ago
3 0
The correct answer is A, B and C
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What shape and bond angles would this molecule have in three dimensions?
Darya [45]

Answer : The shape and bond angle of the given molecule is, bent and 120^o respectively.

Explanation :

In the given molecule, 'Y' is the central atom and 'X' is the neighboring atom. In the given molecule, there are 4 electron pairs that means the hybridization will be sp^3 and the electronic geometry of the molecule will be tetrahedral.

But as there are two atoms around the central atom, the third and fourth position will be occupied by lone pair of electrons. The repulsion between lone and bond pair of electrons is more and hence the molecular geometry will be bent or angular and the bond angle will be, 120^o.

Hence, the shape and bond angle of the given molecule is, bent and 120^o respectively.

5 0
3 years ago
Read 2 more answers
If you have 120. mL of a 0.100 M TES buffer at pH 7.55 and you add 3.00 mL of 1.00 M HCl, what will be the new pH? (The pKa of T
Simora [160]

Answer:

The new pH after adding HCl is 7.07

Explanation:

The formula for calculating pH of a buffer is

pH = pKa + log([Conjugate base]/[Acid])

<u>Before adding HCl,</u>

         7.55 = 7.55 + log([Conjugate base]/[Acid])

⇔      log([Conjugate base]/[Acid])  = 0

⇔     [Conjugate base] = [Acid] = 1/2 x 0.100 = 0.05 M

⇒ Mole of Conjugate base = Mole of Acid = 0.05 M x 0.12 mL = 0.006 mol

<u>After adding HCl (3.00 mL, 1.00 M)</u>

⇒ Mole of HCl = 0.003 x 1 = 0.003 mol)

New volume solution is 120 m L+ 3 mL = 123 mL

HCl is a strong acid, it will convert the conjugate base to acid form, or we can express

Mole of new Conjugate base = 0.006 - 0.003 = 0.003 mol

                ⇒ Concentration = 0.003/0.123 M

Mole of new Acid form = 0.006 + 0.003 = 0.009 mol

                ⇒ Concentration = 0.009/0.123 M

Use the formula

pH = pKa + log([Conjugate base]/[Acid])

    = 7.55 + log(0.003 / 0.009) = 7.07

8 0
3 years ago
If there were 10 grams of a radioactive isotope, how much of the sample would be left after 1 half-life? How much after 2 half-l
Vikentia [17]
One half-life: 5 grams
Two half-lives: 2.5 grams
3 0
3 years ago
What are the possible values of n and ml for an electron in a 5d orbital?
liberstina [14]

Answer:

The answer to your question is n = 5, l = 2, m can be -2, -1, 0, 1 or 2

Explanation:

Data

orbital = 5d

values of n, l, m

Process

1.- Determine the value of n

n is the coefficient of the orbital, in this problem n = 5

2.- Determine the value of l

l takes values depending in the sublevel of energy,

if the sublevel is s  then l = 0

                           p          l = 1

                           d          l = 2

                           f           l = 3

For this problem l = 2

3.- Determine the value of m

when l = 2, m takes values of -2, - 1, 0, 1 or 2

3 0
3 years ago
A science fair volcano bubbles and fizzes. what is taking place?
vaieri [72.5K]
Answer is B. gas formation
7 0
3 years ago
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