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3 years ago

Hellllllllllppppppppppppppp!

Chemistry

2 answers:

s2008m [1.1K]3 years ago

6 0

What is your question??????

Art [367]3 years ago

3 0

Please list your question in the comments.

You might be interested in

How many liters of oxygen gas (O2) are needed to produce 100 kJ of energy at STP? 2C6H6(I) + 1502(g) —> 12CO2(g)+6H2O(g)+3909

makkiz [27]

Answer: 8.59 L of oxygen gas are needed to produce 100 kJ of energy at STP

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number $6.023\times 10^{23}$ of particles.

Standard condition of temperature (STP) is 273 K and atmospheric pressure is 1 atmosphere respectively.

1 mole of every gas occupy volume at STP = 22.4 L

The balanced chemical reaction is:

$2C_6H_6(I)+15O_2(g)\rightarrow 12CO_2(g)+6H_2O(g)$

3909.9 kJ of of energy is produced by = $15\times 22.4=336L$

100 kJ of oxygen gas are needed to produce = $\frac{336}{3909.9}\times 100=8.59L$

7 0

3 years ago

What is the main difference between active transport and passive transport? *

svp [43]

Answer:

There are two major ways that molecules can be moved across a membrane, and the distinction has to do with whether or not cell energy is used. Passive mechanisms like diffusion use no energy, while active transport requires energy to get done.

Explanation:

4 0

2 years ago

True or False: As the ice warms up, the molecules get more energy and move around more from place to place to form liquid water.

Arada [10]

The answer is TRUE.

Hope it helps.

7 0

2 years ago

Read 2 more answers

A piece of wood has a labeled length value of 63.2 cm. You measure its length three times and record the following data: 63.1 cm

Ulleksa [173]

Percent error (%)= $\frac{\left | Accepted value - Measured value \right |}{Accepted value}\times 100$

Accepted value is true value.

Measured values is calculated value.

In the question given Accepted value (true value) = 63.2 cm

Given Measured(calculated values) = 63.1 cm , 63.0 cm , 63.7 cm

1) Percent error (%) for first measurement.

Accepted value (true value) = 63.2 cm, Measured(calculated values) = 63.1 cm

Percent error (%)= $\frac{\left | Accepted value - Measured value \right |}{Accepted value}\times 100$

$Percent error = \frac{\left | 63.2 - 63.1 \right |}{63.2}\times 100$

$Percent error = \frac{0.1}{63.2}\times 100$

$Percent error = 0.00158\times 100$

Percent error = 0.158 %

2) Percent error (%) for second measurement.

Accepted value (true value) = 63.2 cm, Measured(calculated values) = 63.0 cm

Percent error (%)= $\frac{\left | Accepted value - Measured value \right |}{Accepted value}\times 100$

$Percent error = \frac{\left | 63.2 - 63.0 \right |}{63.2}\times 100$

$Percent error = \frac{0.2}{63.2}\times 100$

$Percent error = 0.00316\times 100$

Percent error = 0.316 %

3) Percent error (%) for third measurement.

Accepted value (true value) = 63.2 cm, Measured(calculated values) = 63.7 cm

Percent error (%)= $\frac{\left | Accepted value - Measured value \right |}{Accepted value}\times 100$

$Percent error = \frac{\left | 63.2 - 63.7 \right |}{63.2}\times 100$

$Percent error = \frac{\left | -0.5 \right |}{63.2}\times 100$

$Percent error = \frac{(0.5)}{63.2}\times 100$

$Percent error = 0.00791\times 100$

Percent error = 0.791 %

Percent error for each measurement is :

63.1 cm = 0.158%

63.0 cm = 0.316%

63.7 cm = 0.791%

7 0

3 years ago

What is the area of the throat that contains the vocal cords and produces

aalyn [17]

C larynx hope this helps

7 0

3 years ago