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3 years ago

Hellllllllllppppppppppppppp!

Chemistry

2 answers:

s2008m [1.1K]3 years ago

6 0

What is your question??????

Art [367]3 years ago

3 0

Please list your question in the comments.

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Help me, I’m bad a science.

Sauron [17]

Answer:

Removing the worms is they first key to overcoming this problem. Thus you should ensure that the worms have not spread throughout the house/facility, or caused more damage.

Secondly, you should replace the pipes taht the worms got into, or clean them at most. If it’s simply worm droppings then just clean it, but if it’s more and worse than that alike slime then it is best to remove and replace it.

the only way the worms escaping could affect something is if they decontaminated it, or alas ate or destroyed it. Other than that if they died you could simply replace them, but e things cannot be replaced

Explanation:

You didn’t actually tell us any details so that the best I got from that

can I have brainlest pwease?

8 0

3 years ago

Use the de Broglie's Wave Equation to find the wavelength of an electron moving at 7.3 × 106 m/s. Please show your work. Note: h

ad-work [718]

Answer:

$\lambda=9.96\times 10^{-11}\ m$

Explanation:

The expression for the deBroglie wavelength is:

$\lambda=\frac {h}{m\times v}$

Where,

$\lambda$ is the deBroglie wavelength

h is Planck's constant having value $6.62607\times 10^{-34}\ Js$

m is the mass of electron having value $9.11\times 10^{-31}\ kg$

v is the speed of electron.

Given that v = $7.3\times 10^6\ m/s$

Applying in the equation as:

$\lambda=\frac {h}{m\times v}$

$\lambda=\frac{6.62607\times 10^{-34}}{9.11\times 10^{-31}\times 7.3\times 10^6}\ m$

$\lambda=\frac{10^{-34}\times \:6.626}{10^{-25}\times \:66.503}\ m$

$\lambda=\frac{6.626}{10^9\times \:66.503}\ m$

$\lambda=9.96\times 10^{-11}\ m$

6 0

3 years ago

20.0 g of Nitrogen is produced when oxygen gas reacts with NO gas. 29.8 L of oxygen is required at STP to produce this 20.0 g of

fiasKO [112]

The statement is false as 85675 grams of nitrogen dioxide is produced instead of 20 grams.

Explanation:

Balance equation for the reaction:

2NO + $O_{2}$ ⇒ 2N $O_{2}$

Data given:

mass of nitrogen produced = 20 gram

mass of oxygen = 29.8 litres or 29800 grams

0xygen is the limiting reagent so,

number of moles of oxygen: (atomic mass of 1 mole 32 grams/mole

number of moles = $\frac{mass}{atomic mass of 1 mole}$

putting the values in the equation:

= $\frac{29800}{32}$

= 931.5 moles

1 mole of oxygen reacts to give 2 moles of NO2

931.5 moles of oxygen will give x moles

$\frac{2}{1}$ = $\frac{x}{931.5}$

1862.5 moles of NO2 produced

in grams

mass = number of moles x atomic mass

mass = 1862.5 x 46.00

= 85675 grams

The statement is false as 85675 grams of nitrogen dioxide is produced instead of 20 grams as said in question.

7 0

3 years ago

Why BF3 acts as a Lewis acid???

GaryK [48]

BF3 acts as a Lewis acid when it accepts the lone pair of electrons that NH3 donates.

8 0

3 years ago

Read 2 more answers

How many grams of NaOH are contained in 500 mL of a 0.80 M sodium hydroxide solution?

4vir4ik [10]

This is molarity: moles of solute/liters of solution. (Not molality)

1. Plug in what we know:

500 mL = 0.5 L

0.80 = moles/0.5

0.80*0.5 = moles

moles = 0.4

2. NaOH is given as 40 g/mole, so calculate the grams:

0.4 * 40 = 16 grams

answer: 16 grams

7 0

2 years ago