Answer:

Explanation:
The first step is the <u>calculation of the moles</u> of
and
, so:


Now, in 1 mol of CO2 we have 1 mol of C and in 1 mol of
we have 1 mol of H. Additionally, if we want to calculate the moles of oxygen we need to <u>calculate the grams of C and O</u> and then do the <u>substraction</u> form the initial amount, so:


Now we can <u>convert the grams</u> of O to moles, so:

The next step is to divide all the mol values by the <u>smallest one</u>:



Therefore the formula is 
That is, water has a high heat of vaporization, the amount of energy needed to change one gram of a liquid substance to a gas at constant temperature. Water's heat of vaporization is around 540 cal/g at 100 °C, water's boiling point.
Answer:
2 L
Explanation:
We'll begin by writing the balanced equation for the reaction. This is given below:
2H₂ + O₂ —> 2H₂O
From the balanced equation above, we can see clearly that 1 L of O₂ reacted to 2 L of H₂O.
This implies that 2 L of H₂O can be obtained by the reaction of 1 L of O₂.
Thus, option 3 gives the correct answer to the question.
We have that the Electronegative difference of 2.15 basically makes ionic bonds
Ionic bonds is to be formed
<h3>Bonding</h3>
Generally, the common electronegativity of the team 1 <u>factors </u>are 0.84 and the common <em>electronegativity </em>of the team 17 factors are 2.99.
Group 17 factors are an awful lot greater electronegative than Group 1 elements.
Group 17 consists of F, Cl, Br and I,Group 1 factor that is Na loses 1 electron from its outermost orbit and varieties Na+ cation.
Group 17 Element that is Cl accepts 1 electron in its outermost orbit and Creates Cl- anion. Now, Na+ cation and Cl- anion combines collectively by using ionic bonds.
Hence, the electronegative difference
(2.99-0.84)=2.15
Electronegative difference of 2.15 basically makes ionic bonds
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