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uysha [10]
3 years ago
5

Which of the following is a typical product of nuclear fission?

Physics
2 answers:
xxMikexx [17]3 years ago
6 0
The correct answer for the question that is being presented above is this one: "c. radiation." The typical product of nuclear fission is radiation. Nuclear fission's another product is that<span> two different atoms that are both less massive than the original atom </span>
krok68 [10]3 years ago
6 0

On edge.nuity the answer is C- radiation. Hope this helps you out :)

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The slope of the line tangent to the curve on a position-time graph at a specific time is the
Rudik [331]

Answer:

I do I make a brinliest can you please can me

7 0
3 years ago
Which is an example of a wedge?<br> a. bowl<br> b. spoon<br> c. fork<br> d. knife
elixir [45]
The answer is d.... Knife.

Hope this helped :)
3 0
3 years ago
Determine the index of refraction of glass that is struck by unpolarized light at 53.8 degrees and resulting in a fully polarize
nignag [31]

Answer:

The refractive index of glass, \mu_{g} = 1.367

Solution:

Brewster angle is the special case of incident angle that causes the reflected and refracted rays to be perpendicular to each other or that angle of incident which causes the complete polarization of the reflected ray.

To determine the refractive index of glass:

tan\theta_{P} = \frac{\mu_{g}}{\mu_{a}}                 (1)

where

\mu_{a} = refractive index of glass

\mu_{g} = refractive index of glass

Now, using eqn (1)

tan{53.8^{\circ}} = \frac{\mu_{g}}{1}

\mu_{g} = tan53.8^{\circ}

\mu_{g} = 1.367

5 0
2 years ago
A motorcycle is stopped at a traffic light. When the light turns green, the motorcycle accelerates to a speed of 91 km/h over a
zimovet [89]

Given :

Initial speed , u = 0 m/s .

Final speed , v = 91 km/h = 25.28 m/s .

To Find :

a) Average acceleration .

b ) Assuming the motorcycle maintained a constant acceleration, how far is it from the traffic light after 3.3 s .

Solution :

a )

We know ,by equation of motion :

v^2-u^2=2as\\\\a=\dfrac{v^2-u^2}{2s}\\\\a=\dfrac{25.28^2-0^2}{2\times 47}\ m/s^2\\\\a=6.8\ m/s^2

b)

Also , by equation of motion :

s=ut+\dfrac{at^2}{2}\\\\s=0+\dfrac{6.8\times (3.3)^2}{2}\ m\\\\s=37.02\ m

Hence , this is the required solution .

6 0
3 years ago
Which Equation will you use to solve this question (use the chart at the end of the lesson) While skiing, Sam flies down a hill
ozzi

A.Momentum Equation

m = mass = 75 kg

v = velocity = 18 m/s

P = momentum

Using the momentum equation , momentum is given as

P = mv

P = 75 x 18

P = 1350 kgm/s

4 0
3 years ago
Read 2 more answers
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