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uysha [10]
3 years ago
5

Which of the following is a typical product of nuclear fission?

Physics
2 answers:
xxMikexx [17]3 years ago
6 0
The correct answer for the question that is being presented above is this one: "c. radiation." The typical product of nuclear fission is radiation. Nuclear fission's another product is that<span> two different atoms that are both less massive than the original atom </span>
krok68 [10]3 years ago
6 0

On edge.nuity the answer is C- radiation. Hope this helps you out :)

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Four point charges have the same magnitude of 2.4×10^−12C and are fixed to the corners of a square that is 4.0 cm on a side. Thr
Gwar [14]

Answer:

7.2N/C

Explanation:

Pls see attached file

6 0
3 years ago
2. When the pump removed the air in<br> the bell, the balloon<br> contracted<br> expanded
IRINA_888 [86]

When the pump removed the air in  the bell, the balloon expanded.

<u>Option: B</u>

<u>Explanation:</u>

In order to construct our own environment in the glass jar known as bell jar system, which can be used to explore and consider our larger environment on Earths, for an instance. Here a glass jar that hinges on an airtight rubber basis i.e seals appropriately. At the top of the jar, a bung is connected to it which passed via a metal tube. It has an adjacent flexible tube that goes to a hand vacuum pump and the best hand-powered pump was made with a wine preserver.

When the pump extracts the air from the bell jar, the pressure inside the balloon naturally decreases. The balloon usually has a air pressure around it, which restricts its size, but when this air is extracted and the pressure around it decreases the gas in the balloon will expand and the balloon seems to be inflating. When you release the air back into the bell jar, it will once again compress back to its actual size.

8 0
3 years ago
Near the end of a marathon race, the first two runners are separated by a distance of 45.6 m. The front runner has a velocity of
morpeh [17]

Answer:17.08 s

Explanation:

Given

distance between First and second Runner is 45.6 m

speed of first runner(v_1)=3.1 m/s

speed of second runner(v_2)=4.65 m/s

Distance between first runner and finish line is 250 m

Second runner need to run a distance of 250+45.6=295.6 m

Time required by second runner t=\frac{295.6}{4.65}=63.56 s

time required by first runner to reach finish line=\frac{250}{3.1}=80.64 s

Thus second runner reach the finish line 80.64-63.56=17.08 s earlier

3 0
3 years ago
Consider a blackbody that radiates with an intensity I1I1I_1 at a room temperature of 300K300K. At what intensity I2I2I_2 will t
kap26 [50]

Answer:

Explanation:

We shall apply Stefan's formula

E = AσT⁴

When T = 300

I₁ = Aσ x 300⁴

When T = 400K

I₂ = Aσ x 400⁴

I₂ / I₁ = 400⁴ / 300⁴

= 256 / 81

= 3.16

I₂ = 3.16 I₁ .

5 0
3 years ago
Frost wedging occurs when water seeps into a crack in a rock, freezes, and causes the crack in the rock to widen.
Ilia_Sergeevich [38]

Answer:

the answer is true.

3 0
3 years ago
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