Given :
Mass of box , m = 250 kg.
Force applied , F = 285 N.
The value of the incline angle is 30°.
the coefficient of dynamic friction is
.
To Find :
The speed with which the box is moving with, assuming it takes 4 seconds to reach the top of the incline.
Solution :
Net force applied in box is :

Acceleration ,
.
By equation of motion :

Therefore, the speed of box is 12.04 m/s.
Hence, this is the required solution.
Answer:
Explanation:
Given
mass flow rate=0.3 kg/s
diameter of pipe=5 cm
length of pipe=10 m
Inside temperature=22
Pipe surface =100
Temperature drop=30
specific heat of vapor(c)=2190 J/kg.k
heat supplied 
Heat due to convection =hA(100-30)




19,710=122.538 h

On a speed/time graph, the height of the line at any point
shows the speed at that moment. If the line is horizontal,
then its height isn't changing, meaning that the speed isn't
changing. It's constant. The change is zero, until the line
starts rising or falling.
Answer:
1) 
2) 
Explanation:
Given:
- mass of heavier student,

- mass of lighter student,

- velocity of the heavier student after the mutual push,

1)
Since they push each other and we are neglecting any friction that means we can consider this as a perfectly elastic collision. So the momentum of the two bodies will be equal and in opposite direction.
Since momentum is a vector quantity so the total momentum of the system as a whole will be zero.
2)
<u>From the condition of elastic collision:</u>



