1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Jobisdone [24]
3 years ago
6

In a power plant, pipes transporting superheated vapor are very common. Superheated vapor flows at a rate of 0.3 kg/s inside a p

ipe that is of diameter 5 cm and length10 m. The pipe is located in a power plant at a temperature of 22°C, and has a uniform pipe surface temperature of 100°C. If the temperature drop between the inlet and exit of the pipe is 30°C and the specific heat of the vapor is 2190 J/kg·K, determine the heat transfer coefficient as a result of convection between the pipe surface and the surroundings.
Physics
1 answer:
grigory [225]3 years ago
5 0

Answer:h=160.84 W/m^2-K

Explanation:

Given

mass flow rate=0.3 kg/s

diameter of pipe=5 cm

length of pipe=10 m

Inside temperature=22

Pipe surface =100

Temperature drop=30

specific heat of vapor(c)=2190 J/kg.k

heat supplied Q=mc\Delta T=0.3\times 2190\times (30)

Heat due to convection =hA(100-30)

A=\pi d\cdot L

A=\pi 0.05\times 10=1.571 m^2

Q_{convection}=h\times 1.571\times (100-22)=122.538 h

Q=Q_{convection}

19,710=122.538 h

h=160.84 W/m^2-K

You might be interested in
How many different values of l are possible for an electron with principal quantum number n=5?
lions [1.4K]

Answer:

different value to l if n=5 are 0,1,2,3,4

7 0
3 years ago
Why is earth the only planet on which water exists in a liquid state
Gennadij [26K]
This is due to earths location in the solar system. Earth is in the habitat zone or the Goldie locks zone, in this zone it's not too hot or not too cold for water to exist. Other planets in different star systems have liquid oceans due to them being in the habitat zone.
7 0
3 years ago
Density is given in ____.<br> a. Pa/cm3<br> c. g/s2<br> b. N/m2<br> d. g/cm3
Ainat [17]
Density is defined as  [mass] / [volume] .

The only choice listed with those physical dimensions is 'd' .
3 0
3 years ago
Planet 1 orbits Star 1 and Planet 2 orbits Star 2 in circular orbits of the same radius. However, the orbital period of Planet 1
hichkok12 [17]

Answer:

The mass of Star 2 is Greater than the mass of Start 1. (This, if we suppose the masses of the planets are much smaller than the masses of the stars)

Explanation:

First of all, let's draw a free body diagram of a planet orbiting a star. (See attached picture).

From the free body diagram we can build an equation with the sum of forces between the start and the planet.

\sum F=ma

We know that the force between two bodies due to gravity is given by the following equation:

F_{g} = G\frac{m_{1}m_{2}}{r^{2}}

in this case we will call:

M= mass of the star

m= mass of the planet

r = distance between the star and the planet

G= constant of gravitation.

so:

F_{g} =G\frac{Mm}{r^{2}}

Also, if the planet describes a circular orbit, the centripetal force is given by the following equation:

F_{c}=ma_{c}

where the centripetal acceleration is given by:

a_{c}=\omega ^{2}r

where

\omega = \frac{2\pi}{T}

Where T is the period, and \omega is the angular speed of the planet, so:

a_{c} = ( \frac{2\pi}{T})^{2}r

or:

a_{c}=\frac{4\pi^{2}r}{T^{2}}

so:

F_{c}=m(\frac{4\pi^{2}r}{T^{2}})

so now we can do the sum of forces:

\sum F=ma

F_{g}=ma_{c}

G\frac{Mm}{r^{2}}=m(\frac{4\pi^{2}r}{T^{2}})

in this case we can get rid of the mass of the planet, so we get:

G\frac{M}{r^{2}}=(\frac{4\pi^{2}r}{T^{2}})

we can now solve this for T^{2} so we get:

T^{2} = \frac{4\pi ^{2}r^{3}}{GM}

We could take the square root to both sides of the equation but that would not be necessary. Now, the problem tells us that the period of planet 1 is longer than the period of planet 2, so we can build the following inequality:

T_{1}^{2}>T_{2}^{2}

So let's see what's going on there, we'll call:

M_{1}= mass of Star 1

M_{2}= mass of Star 2

So:

\frac{4\pi^{2}r^{3}}{GM_{1}}>\frac{4\pi^{2}r^{3}}{GM_{2}}

we can get rid of all the constants so we end up with:

\frac{1}{M_{1}}>\frac{1}{M_{2}}

and let's flip the inequality, so we get:

M_{2}>M_{1}

This means that for the period of planet 1 to be longer than the period of planet 2, we need the mass of star 2 to be greater than the mass of star 1. This makes sense because the greater the mass of the star is, the greater the force it applies on the planet is. The greater the force, the faster the planet should go so it stays in orbit. The faster the planet moves, the smaller the period is. In this case, planet 2 is moving faster, therefore it's period is shorter.

6 0
3 years ago
A person walks 9 meters to the right and 8 meters to the left what's the distance and displacement​
nordsb [41]
The distance is 17 and the displacement is 1
5 0
2 years ago
Read 2 more answers
Other questions:
  • In most cases, what happens to a liquid when it cools?
    11·1 answer
  • How is potential energy unique?
    14·1 answer
  • Air "breaks down" when the electric field strength reaches 3 x 10^6 N/C, causing a spark. A parallel-plate capacitor is made fro
    6·2 answers
  • A ship is moving with a constant acceleration of 36km/hr2 in a fixed direction speeds up from 12 km/hr to 18km/hr. Find the dist
    14·1 answer
  • What is an atomic nucleus​
    14·1 answer
  • Listening to the radio, you can hear two stations at once. Describe this wave interaction
    12·2 answers
  • Which of the following is the primary function of groundwater?
    9·2 answers
  • A box is being moved with a velocity (v) by a force P (parallel to v) along a level horizontal floor. The normal force is (Fn),
    9·1 answer
  • Can you answer this math homework? Please!
    12·1 answer
  • What is environment balance
    13·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!