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lesantik [10]
3 years ago
8

Graph the linear equation.find three points that solve the equation, then plot on the graph. -4y=x-18

Mathematics
2 answers:
zubka84 [21]3 years ago
6 0

Answer:


Step-by-step explanation:

Answer:


Step-by-step explanation:

First the solution to the equation

-4y = x - 18   Divide by - 4. Watch your signs.

-4y / -4 = x/-4 + 18/-4            Do the division. Notice the 18 needs to be divided by - 4 as well as the other two terms.

y = (-1/4)x - 4.5

Second the graph. See below.

Your original equation is what was graphed.

Third: The table with the points added to the graph.

Sample Calculation

x = 10

-4y = 10 - 18

-4y = - 8

y = -8/-4

y = 2

Point (10,2)

The graph on the right includes the table with 3 points plotted.

kirill [66]3 years ago
5 0

Step-by-step explanation:-

-4y goes on the y axis

and 18 goes on the x axis

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7×10^8

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A vector given in component form is presented as <x, y>, where <em>x</em> represent the horizontal displacement and <em>y</em> represents the vertical displacement

<u>The </u><u>vector </u><u>that </u><u>maps </u><u>the figure ABCD to its </u><u>image </u>A'B'C'D' is <u><3, -7></u>

The reason the above value is correct is as follows:

The coordinates of the vertices of the preimage ABCD are A(-6, 4), B(-1, 4), C(3, 1), and D(-5, 1)

The coordinates of the vertices of the image A'B'C'D' are A'(-3, -3), B'(2, -3), C'(6, -6), and D'(-2, -6)

The component form of the vector that maps the figure to its image is given as follows;

\begin{array}{|c|r|l|c|}Differences&x-value \, (I_x - P_x)& y - value  \, (I_y - P_y)& Vector\\A' \ and \  A &-3 - (-6) = 3&-3 - 4 = -7& \\B' \ and \ B&2 - (-1) = 3&-3 - 4 = -7&\\C' \ and \ C&6 - 3 = 3&-6 - 1 = -7&\\D' \ and \ D&-2 - (-5) = 3&-6 - 1 = -7&\end{array}

Therefore,

The component form of the vector that maps the figure ABCD to its image A'B'C'D' is <3, -7>

Learn more about the component form of a vector here:

brainly.com/question/19380692

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