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3 years ago

Convert 2 3/7 to an improper fraction

1 answer:

6 0

Answer:The mixed number 2 3/7 can be converted to the improper fraction 17/7. The easiest way to do this is to multiply the denominator of the fraction (7 in...

Step-by-step explanation:

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Ms. Fielding drove 3.8 miles to the park, then 4.3 miles to baseball field, and then 6.2 miles back home. What is the total numb

Brilliant_brown [7]

14.3 miles.

6.2+3.8=10
10+4.3=14.3

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3 years ago

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Help for question 7 please

scoray [572]

◆ COMPLEX NUMBERS ◆

$given \: expression \: is \: - \\ \\ - 3 {i}^{4} + 2 {i}^{3} + 2 {i}^{2} + \sqrt{ - 9} \\ \\ we \: know \: that \: , \: \\ i = \sqrt{ - 1} \\ \\ {i}^{2} = - 1 \\ \\ {i}^{3 } = - i \\ \\ {i}^{4} = 1 \\ \\ \\ - 3 {i}^{4} + 2 {i}^{3} + 2 {i}^{2} + \sqrt{9} i \\ = - 3 {i}^{4} + 2 {i}^{3} + 2 {i}^{2} + 3i \\ \\ using \: the \: above \: properties \: of \: iota \: (i) \\ \\ = - 3(1) + 2( - i) + 2( - 1) + 3i \\ \\ = - 3 - 2i - 2 + 3i \\ \\ = (- 5 + i) \: \: \: ans.$

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3 years ago

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Find the slope of the line of best fit shown below.

grandymaker [24]

The Answer is A, 1/2

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3 years ago

Write in standard form 2+4i over 1+i

Levart [38]

So hmm a conjugate, is pretty much just, the same binomial, but with a different sign in the middle, so, a + b, has a conjugate of a - b
or -a + b, has a conjugate of - a - b, or c - d, has a conjugate of c +d, and so on

anyway, the idea being, to "rationalize" the expression, namely, getting rid of the pesky radical in the denominator

so, we'll multiply the expression by 1, since anything times 1 is just itself

however, bear in mind, that 1, can be a/a, or b/b, or cheese/cheese, or anything/anything

so, we'll multiply the top and bottom of the fraction, by the conjugate of the denominator

anyhow, that said $\bf \cfrac{2+4i}{1+i}\cdot \cfrac{1-i}{1-i}\implies \cfrac{(2+4i)(1-i)}{(1+i)(1-i)}\implies \cfrac{2-2i+4i-4i^2}{1-i^2}\\\\
-----------------------------\\\\
\textit{recall that }i^2=-1\\\\
-----------------------------\\\\
 \cfrac{2-2i+4i-4(-1)}{1-(-1)}\implies \cfrac{2+2i+4}{2}\implies \cfrac{6+2i}{2}\implies \cfrac{6}{2}+\cfrac{2i}{2}
\\\\\\
\boxed{3+i}$

7 0

3 years ago

A) (x-1)^3+ 3x(x-4)+2=x^3<br> B) x^3 +6x +12x +8=0

Maksim231197 [3]

Answer: I'll solve A) since there is a lot of work to be shown.

Step-by-step explanation:

(x−1)³+3x(x−4)+2=x³

Use binomial theorem to expand (x−1)³

x³- 3x² + 3x - 1 + 3x(x-4) + 2=x³

Use distributive property on 3x(x-4)

x³- 3x² + 3x - 1 + 3x²-12x + 2=x³

Add like terms

x³ −9x + 1 =x³

Subtract x³ from both sides.

x³ −9x +1 -x³ = 0

Add x³ and -x³

−9x+1=0

Subtract 1 from both sides. Anything subtracted from zero gives its negation.

−9x=−1

Divide both sides by -9.

x= 1/9

4 0

3 years ago

Convert 2 3/7 to an improper fraction​

Convert 2 3/7 to an improper fraction